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slamgirl [31]
3 years ago
12

4. What is the tan gential velocity of an object moving in a path of radius 2m with an angular velocity of

Physics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

<em>6m/s</em>

Explanation:

The tangential velocity is the product of the linear velocity and the radius. This is expressed as;

v = wr

w is the angular velocity = 3rad/s

r is the radius = 2m

Substitute

v = 3 * 2

v = 6m/s

Hence the tangential velocity of the object is 6m/s

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4 years ago
An echo is heard from a cliff 3.71 s after a rifle is fired. How many feet away is the cliff
LenKa [72]

The cliff is 2042 ft away.

We know that the speed of sound in air is directly proportional to the absolute temperature.

First convert the Fahrenheit temperature to Celsius;

 °C = 5/9(44.5 - 32)

°C = 6.9 °C

Applying the formula;

V1/V2 = √T1/T2

Where; V1 = velocity of sound in air at  0°C

V2 = Velocity of sound in air at 6.9 °C

1087/V2 = √273/279.9

V2= 1101 ft/s

Given that; V = 2s/t

Where s is the distance of the cliff

t is the time taken

1101 ft/s = 2s/3.71 s

s = 1101 ft/s × 3.71 s/2

s = 2042 ft

Learn more:brainly.com/question/15381147

3 0
3 years ago
A certain moving electron has a kinetic energy of 0.991 × 10−19 J. Calculate the speed necessary for the electron to have this e
alisha [4.7K]

Answer: The speed necessary for the electron to have this energy is 466462 m/s

Explanation:

Kinetic energy is the energy posessed by an object by virtue of its motion.

K.E=\frac{1mv^2}{2}

K.E= kinetic energy = 0.991\times 10^{-19}J

m= mass of an electron = 9.109\times 10^{-31}kg

v= velocity of object = ?

Putting in the values in the equation:

0.991\times 10^{-19}J=\frac{1\times 9.109\times 10^{-31}kg\times v^2}{2}

v=466462m/s

The speed necessary for the electron to have this energy is 466462 m/s

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