A SPIDER CRAWLS VERTICALLY ON A WALL Y VS TIME T WHAT IS THE AVERAGE VELOCITY OF THE SPIDER BETWEEN THE TIME T=4s and t=10s
1 answer:
Answer:
The question is incomplete,
the displacement time graph is missing. Check attachment for the graph.
Explanation:
Average velocity can be find by using
Average velocity = change in displacement / time taken
A.V = ∆y / ∆t
So, at time t1 = 4s, the position of the body is at 2m
y1 = 2m
Also, at time t2 = 10s, the position of the body is at 5m
y2 = 5m.
So,
A.V = ∆y / ∆t
A.V = (y2 - y1) / (t2 - t1)
A.V = (5 - 2) / (10 - 4)
A.V = 3 / 6
A.V = 0.5m/s
So, the average velocity is 0.5m/s
You might be interested in
Answer:
The pressure is constant, and it is P = 150kpa.
the specific volumes are:
initial = 0.062 m^3/kg
final = 0.027 m^3/kg.
Then, the specific work can be written as:
The fact that the work is negative, means that we need to apply work to the air in order to compress it.
Now, to write it in more common units we have that:
1 kPa*m^3 = 1000J.
-5.25 kPa*m^3/kg = -5250 J/kg.
Answer:
Explanation:
Given
time of contact between bat and ball is
suppose u is the incoming velocity and v is the final velocity after collision
Impulse exerted is given by change in momentum of the particle.
Initial momentum
Final momentum
Change in momentum
Impulse