A SPIDER CRAWLS VERTICALLY ON A WALL Y VS TIME T WHAT IS THE AVERAGE VELOCITY OF THE SPIDER BETWEEN THE TIME T=4s and t=10s
1 answer:
Answer:
The question is incomplete,
the displacement time graph is missing. Check attachment for the graph.
Explanation:
Average velocity can be find by using
Average velocity = change in displacement / time taken
A.V = ∆y / ∆t
So, at time t1 = 4s, the position of the body is at 2m
y1 = 2m
Also, at time t2 = 10s, the position of the body is at 5m
y2 = 5m.
So,
A.V = ∆y / ∆t
A.V = (y2 - y1) / (t2 - t1)
A.V = (5 - 2) / (10 - 4)
A.V = 3 / 6
A.V = 0.5m/s
So, the average velocity is 0.5m/s
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Answer:
F = 51.3°
Explanation:
The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:
where,
W = Weight of Wagon = 150 N
θ = Angle of Inclinition = 20°
Therefore,
<u>F = 51.3°</u>