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Romashka-Z-Leto [24]
3 years ago
13

If a board game was

Mathematics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

28%Right?

hdjdkdkdkdkdkdkdkdk

jdjdkdodidkdk

You might be interested in
Solve for m∠WUV if m∠TUV= 100 and m∠TUW = 60.
Veronika [31]

Answer:

20

Step-by-step explanation:

100 + 60 = 160

There are 180 degrees in a triangle so we do 180-160 = 20

6 0
3 years ago
The area of a book cover is 63.8 in². The width of the book is the difference of the length and 3 inches. Let x represent the bo
Mazyrski [523]
In this item, we are already given that the length of the rectangular book can be represented by the variable x. In this way, the width, which was described to be the difference of the length and 3 inches, can be expressed as x - 3. 

The area of the triangle is rectangle is calculated by multiplying the length, x, and the width, which was derived to be x - 3.

                 Area = Length x width
                 Area = (x)( x - 3)

Putting in the value of the area, we have the final answer as,
               x(x - 3) = 63.8 in²

Hence, the final answer is the first answer. 
3 0
3 years ago
Find the measure of a central angle that intercepts an arc of 3 inches in a circle whose radius is 8 inches.
Tresset [83]

Answer:

option (A)

central angle = 0.375 rad

Step-by-step explanation:

Given in the question,

radius of the circle = 8 inches

arc of the circle = 3 inches

To find,

measure of a central angle

Central angles are subtended by an arc between those two points.

Formula to use:

<h3>     s = (r) (θ)</h3>

<em>where r = radius </em>

<em>            s = arc length </em>

<em>            θ = angle in radians</em>

<em />

Plug in the values in the equation

<h3>3 = (8) (θ)</h3><h3>θ = 3/8 </h3><h3>0.375 rad</h3>

5 0
4 years ago
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
The ratio of boys to girls at the beach cleanup was 7:8. If there were 42 boys, how many girls were there?
sergey [27]

Answer: 48

Step-by-step explanation:

7:8 is equal to 42:48 because its multiplying 6 to the original numbers


3 0
3 years ago
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