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g100num [7]
3 years ago
11

In a binary-star system that produces a nova, the white dwarf pulls matter from the companion star. The matter forms an accretio

n disk that orbits the white dwarf. Then a specific sequence of events must take place for a nova event to occur. Rank the steps leading up to the observed nova event in chronological order from first to last.
Physics
1 answer:
Studentka2010 [4]3 years ago
4 0

As a head-up, it is important to notice that a white dwarf only shines thanks to the stored energy and light, because a white dwarf doesn't have any hydrogen left to perform nuclear fusion.

Now the process:

First, the white dwarf accumulates all the extracted matter from its companion, onto its own surface. This extra matter increases the white dwarf's temperature and density.

After a while, the star reaches about 10 million K, so nuclear fusion can begin. The hydrogen that has been "stolen" from the other star and accumulated in the white dwarf's surface it's used for the fusion, dramatically increasing the star's brightness for a short time, causing what we know as a Nova.

As this fuel its quickly burnt out or blown into space, the star goes back to its natural white dwarf state. Since the white dwarf nor the companion star are destroyed in this process, it can happen countless of times during their lifespan.

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A tough kid on a tricycle has combined mass 32 kg. She starts from rest and travels 3.5 m in 2.5 s. What is the net force used t
Darina [25.2K]

Answer:

<h3>F = 35.84N</h3>

Explanation:

Force = mass * acceleration (Newton's second law of motion)

Given

Mass = 32kg

Get the acceleration using the expression d = 1/2at^2

3.5 = 1/2 (a)2.5^2

3.5 = 3.125a

a = 3.5/3.125

a = 1.12m/s^2

Get the net force;

F =  3.2 * 1.12

F = 35.84N

Hence the net force used to accelerate is 35.84N

8 0
3 years ago
In your opinion, is "avoiding" an effective conflict management strategy? Why or why not?
soldi70 [24.7K]
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4 0
3 years ago
Read 2 more answers
A 50kg boy runs at a speed of 10.0m/s and jumpsonto a cart
andriy [413]

Answer:

the mass of the cart is 150 kg

Explanation:

given,

mass of boy(m) = 50 kg

speed of boy (v)= 10 m/s                  

initial velocity of cart (u) = 0                    

final velocity of cart(V) = 2.5 m/s              

mass of the cart(M) = ?                              

m v + M u = (m + M ) V......................(1)

50× 10 + 0 = (50 + M ) 2.5

M =\dfrac{500}{2.5} - 50

M = 150 Kg                                          

hence, the mass of the cart is 150 kg

4 0
3 years ago
Read 2 more answers
Tommy runs around a track whose circumference is 400 meters. He runs a single lap in a time of 62 seconds. What is Tommy’s displ
bija089 [108]

Answer:

<h2>Angular Displacement 6.28 radians</h2>

Explanation:

for circular motion we are expected to solve for Angular Displacement it is measured in radian

Measurement of Angular Displacement.

we can measure it using the following relation

∅= s/r

where

s = the distance travelled by the body, and

r = radius of the circle along which it is moving.

given that

circumference c,  s= 400 m

r= ?

we have to solve for the radius

we know that circumference

c= 2\pi r

400= 2*3.142*r

400= 6.282*r

divide both sides by 6.284 we have

400/6.284

r= 63.63 m

Angular  displcament

∅= 400/63.63

∅= 6.28 radians

8 0
3 years ago
The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
chubhunter [2.5K]

Answer:

The angular separation equals 0.35^{o}

Explanation:

We have according to Snell's law

n_{1}sin(\theta _{1})=n_{2}sin(\theta _{2})

\therefore \theta _{2}=sin^{-1}(\frac{n_{1}sin(\theta _{1})}{n_{2}})

Using this equation for both the colors separately we have

\theta _{red}=sin^{-1}(\frac{sin(23.90^{o})}{1.62})\\\\\theta _{red}=14.48^{o}

Similarly for violet light we have

\theta _{violet}=sin^{-1}(\frac{sin(23.90^{o})}{1.660})\\\\\theta _{violet}=14.13^{o}

Thus the angular separation becomes

\Delta \theta =14.48-14.13=0.35^{o}

6 0
3 years ago
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