Answer:
Explanation:
The equation that relates electric field strength and force that a charge experiments by it is F=qE.
Newton's 2nd Law states F=ma, which for our case will mean:
We know from accelerated motion that
In our case the proton is released from rest, so and we get
Substituting, we get our final velocity equation:
For the <em>proton </em>we know that and
. Writing in S.I. d=0.0025m, we obtain:
Answer:
<em>The motorboat ends up 7.41 meters to the west of the initial position </em>
Explanation:
<u>Accelerated Motion </u>
The accelerated motion describes a situation where an object changes its velocity over time. If the acceleration is constant, then these formulas apply:
The problem provides the conditions of the motorboat's motion. The initial velocity is 6.5 m/s west. The final velocity is 1.5 m/s west, and the acceleration is to the east. Since all the movement takes place in one dimension, we can ignore the vectorial notation and work with the signs of the variables, according to a defined positive direction. We'll follow the rule that all the directional magnitudes are positive to the east and negative to the west. Rewriting the formulas:
Solving the first one for t
We have
Using these values
We now compute x
The motorboat ends up 7.41 meters to the west of the initial position