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HACTEHA [7]
3 years ago
7

Daniela is writing a report on the country of Australia, and she wants to tell how far Australia is from Florida, where she live

s.
Which of the following units of measure would be most appropriate for describing the distance between Florida and Australia?


A. kilometers

B. kilometers/second

C. light-years

D. meters
Physics
1 answer:
o-na [289]3 years ago
8 0

Answer:

A. kilometers

Explanation:

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A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the
Margaret [11]

Hi there!

\boxed{\omega = 0.38 rad/sec}

We can use the conservation of angular momentum to solve.

\large\boxed{L_i = L_f}

Recall the equation for angular momentum:

L = I\omega

We can begin by writing out the scenario as a conservation of angular momentum:

I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)

I_m = moment of inertia of the merry-go-round (kgm²)

\omega_m = angular velocity of merry go round (rad/sec)

\omega_f = final angular velocity of COMBINED objects (rad/sec)

I_b = moment of inertia of boy (kgm²)

\omega_b= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

I = MR^2

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

\omega = \frac{v}{r}

L_b = MR^2(\frac{v}{R}) = MRv

Plug in the given values:

L_b = (20)(3)(5) = 300 kgm^2/s

Now, we must solve for the boy's moment of inertia:

I = MR^2\\I = 20(3^2) = 180 kgm^2

Use the above equation for conservation of momentum:

600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}

8 0
3 years ago
Which item is not considered electromagnetic energy?
suter [353]
Sound waves are known to be the one that's not considered as a type of electromagnetic energy. As for microwaves and x-rays, they tend to share the same frequencies that can be considered as electromagnetic, and sound waves have a different frequency than them.
5 0
3 years ago
Most of the really bright stars in our sky are NOT among the stars that are very close to us. Why then do they look so bright to
Yanka [14]

Answer:

stars will emit more light due to their Luminosity, so they look very bright.

Explanation:

Luminous refers to..,

  • The total amount of energy radiated by a star or other celestial object per second.
  • Therefore it is the power output of a star.

Most of the really bright stars in our sky are not that very close to us yet they look bright because of the Luminosity of the star.

These stars are intrinsically so luminous.

A star's power output across all wavelengths is called its bolometric luminosity.

A star with large luminosity will have more measure of radiated electromagnetic power meaning.

so it will emit more light than a low luminosity star.

Hence,

those stars can easily be seen even across great distance.

learn more about  Luminosity of the star here:

<u>brainly.com/question/13912549</u>

<u />

#SPJ4

6 0
2 years ago
What does the Pauli exclusion principle state? . . A.Electrons will be added to an atom at the lowest possible level or sublevel
BARSIC [14]
The Pauli exclusion principle state that : D. Two electrons occupy the same orbital only if they have opposite spins

This happen because he stated that in an atom or molecule, two electrons CANNOT have same four electronic quantum numbers

hope this helps
5 0
3 years ago
Imagine that someone pushes one marble toward a motionless marble. Would there still be action-reaction forces involved in the c
Finger [1]
All the energy that was in the first marble was transfers into the second marble
8 0
4 years ago
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