3 years ago

HELPPP. PHYSICAL SCIENCE MECHANICAL ENERGY LAB

Physics

1 answer:

Advocard [28]3 years ago

4 0

Answer:

https://www.teacherspayteachers.com/Browse/Search:mechanical%20energy%20labs

Explanation:

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3 years ago

A 645-turn coil with a 20.250 m 2 area is spun in Earth’s 5.00×10 −5 T magnetic field, producing a 1.25-V maximum emf. A

Dmitriy789 [7]

Answer:

$\omega = 1.914\ rad/s$

Explanation:

Given,

Number of turns, N = 645 N

Area, A = 20.25 m²

Earth Magnetic field, B = 5 x 10⁻⁵ T

Maximum Emf = 1.25 V.

Angular velocity, ω = ?

Using Induced Emf formula

$\varepsilon = NAB\omega$

$\omega= \dfrac{\varepsilon}{NAB}$

$\omega= \dfrac{1.25}{645\times 20.25\times 5\times 10^{-5}}$

$\omega = 1.914\ rad/s$

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3 years ago

An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only

Gnesinka [82]

Answer:

15.75 m/s

Explanation:

v = Velocity of the combined mass of astronaut and tools = 1.8 m/s

$m_1$ = Mass of astronaut = 124 kg

$m_2$ = Mass of tools = 16 kg

$v_1$ = Velocity of astronaut = 0

$v_2$ = Velocity of tools

As linear momentum is conserved

$m_1v_1 + m_2v_2 =(m_1 + m_2)v\\\Rightarrow v_2=\frac{(m_1 + m_2)v-m_1v_1}{m_2}\\\Rightarrow v_2=\frac{(124+16)\times 1.8-124\times 0}{16}\\\Rightarrow v_2=15.75\ m/s$

The velocity of the tools is 15.75 m/s

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3 years ago