HELPPP. PHYSICAL SCIENCE MECHANICAL ENERGY LAB

HELP PLEASE!!!!! pulleys, wheels, and axels.

babymother [125]

The answer is C . 500 N

6 0

4 years ago

A particle of mass 4.0 kg is constrained to move along the x-axis under a single force F(x) = −cx3 , where c = 8.0 N/m3 . The pa

Pie

Answer:4.58 m/s

Explanation:

Given

mass of Particle $m=4 kg$

$F=-cx^3$

$a=\frac{F}{m}$

$a=-\frac{cx^3}{m}$

$a=-\frac{8x^3}{4}$

$a=-2x^3$

$v\frac{\mathrm{d} v}{\mathrm{d} x}=-2x^3$

$vdv=-2x^3dx$

integrating

$\int_{6}^{v_b}vdv=\int_{1}^{-2}-2x^3dx$

$\frac{v_b^2-6^2}{2}=-\frac{1}{2}\left [ \left ( -2\right )^4-\left ( 1\right )^4\right ]$

$\frac{v_b^2-36}{2}=-0.5\times 15$

$v_b^2=36-15$

$v_b=\sqrt{21}$

$v_b=4.58 m/s$

6 0

3 years ago

A 15 kg block is on a ramp which is inclined at 20o above the horizontal. It is connected by a string to a 19 kg mass which hang

12345 [234]

Answer:

The magnitude of the acceleration of the 19 kg block is 1.414 m/s²

Explanation:

From Newton's second law of motion;

$F_{Net} = ma$

where;

m is the mass of the objects involved, kg

a is the acceleration of the object, m/s²

different forces on the block and string

⇒force due to 15 kg block

=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396

= 138.12 N

⇒Tensional Force on 19 kg mass:

T = mg = 19×9.8 = 186.2 N

$F_{Net} = T-mg = a(m_1+m_2)$

186.2 - 138.12 = a(15+19)

48.08 = a(34)

a = 48.08/34

a = 1.414 m/s²

Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²

7 0

4 years ago

What energy is calculated from an object’s mass, height, and the acceleration due to gravity? A. elastic kinetic B. elastic pote

Alex777 [14]

Answer: C. gravitational kinetic

Explanation: Gravitational potential energy is the energy calculated from an object's mass height and the acceleration due to gravity. The gravitational potential energy is the energy an object has as a result of the position of the object in a gravitational field.

3 0

3 years ago

Read 2 more answers

For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.

NeX [460]

(1) The critical angles for the fused quartz is 44⁰,

(2) The critical angles for the polystyrene is 39⁰.

(3) The critical angles for the sodium chloride is 41⁰.

<h3>What is Critical angles?</h3>

In optics, the critical angle is the topmost angle at which a shaft of light traveling in one transparent medium can strike the boundary between that medium and another with a lower refractive indicator without being fully reflected within the first

Critical angles for the different medium.

θ $=sin^{-1}\frac{n_{2} }{n_{1} }$

where;

$n_{2}$ is the refractive index of air = 1

$n_{1}$ is the refractive index of the given substances.

Refractive index of quartz glass = 1.46

Refractive index of polystyrene = 1.59

Refractive index of sodium chloride = 1.54

Critical angles for quartz glass:

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.46}\\$

$\theta_{\text {crit }}=44^{o}$

Critical angles for polystyrene

$$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.59}\\\\$

$\theta_{\text {crit }}=39^{\circ}$

Critical angles for Sodium Chloride

$$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.54}\\$

$\theta_{\text {crit }}=41^{o}$

Thus, the critical angles for the quartz glass is 44⁰, the critical angles for the polystyrene is 39 ⁰ and the critical angles for the sodium chloride is 41⁰.

To know more about critical angle visit:
brainly.com/question/3314727

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I understand that the question you are looking for is:

"For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.

(a) Fused Quartz

(b) Polystyrene

(c) Sodium chloride"

8 0

2 years ago