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Novosadov [1.4K]
3 years ago
13

HELPPP. PHYSICAL SCIENCE MECHANICAL ENERGY LAB

Physics
1 answer:
Advocard [28]3 years ago
4 0

Answer:

https://www.teacherspayteachers.com/Browse/Search:mechanical%20energy%20labs

Explanation:

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In a certain chemical process, a lab technician supplies 292 J of heat to a system. At the same time, 68.0 J of work are done on
vekshin1

Answer:

The increase in the internal energy of the system is 360 Joules.

Explanation:

Given that,

Heat supplied to a system, Q = 292 J

Work done on the system by its surroundings, W = 68 J

We need to find the increase in the internal energy of the system. It can be given by first law of thermodynamics. It is given by :

dE=dQ+dW\\\\dE=292\ J+68\ J\\\\dE=360\ J

So, the increase in the internal energy of the system is 360 Joules. Hence, this is the required solution.

3 0
2 years ago
One of the main factors driving improvements in the cost and complexity of integrated circuits (ICs) is improvements in photolit
nika2105 [10]

Answer:

0.000003782 m

0.000001891 m

0.000001197125 m

Explanation:

\lambda = Wavelength = 248 nm

D = Diameter of beam = 1 cm

f = Focal length = 0.625 cm

The angle is given by

\theta=\dfrac{1.22\lambda}{D}

The width is given by

d=2\theta f\\\Rightarrow d=2\dfrac{1.22\lambda f}{D}\\\Rightarrow d=2\dfrac{1.22\times 248\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.000003782\ m

The required width is 0.000003782 m

Minimum resolvable line separation is given by

\dfrac{0.000003782}{2}=0.000001891\ m

The minimum resolvable line separation between adjacent lines is 0.000001891 m

when \lambda=157\ nm

d=2\dfrac{1.22\times 157\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.00000239425\ m

The new minimum resolvable line separation between adjacent lines is

\dfrac{0.00000239425}{2}=0.000001197125\ m

6 0
3 years ago
A particle travels clockwise on a circular path of diameter​ R, monitored by a sensor on the circle at point​ P; the other endpo
kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}

With this function we should only calculate the derivate in function of c

\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}

That is the rate of change of \theta.

b) At this point we need only make a substitution of 0 for c in the equation previously found.

\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}

Hence we have finally the rate of change when c=0.

6 0
3 years ago
A coach shouts "Go!" from the finish line of a 100.0-m track to the runners.
irina [24]

Answer:

a. Speed = 342.5 meters per seconds.

b. Wavelength = 2.0 meters

Explanation:

Given the following data;

Distance = 100m

Time = 292 milliseconds to seconds = 292/1000 = 0.292 seconds

Frequency = 171 Hz

a. To find the speed of sound in air;

Speed = distance/time

Speed = 100/0.292

Speed = 342.5 m/s

b. To find the wavelength;

Wavelength = speed/frequency

Wavelength = 342.5/171

Wavelength = 2.0 m

5 0
2 years ago
Which of these is NOT an effect of humor?
IgorLugansk [536]
Feelings of jealousy and envy
7 0
3 years ago
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