Answer:
(a) Acceleration = 0.1063 m/s^2 (Second team wins)
(b) Tension in rope = 65.106 N
Explanation:
Total mass of first team = 68 * 9 = 612 kg
Total force of first team = 1350 * 9 = 12150 N
Total mass of second team = 73 * 9 = 657 kg
Total force of seconds team = 1365 * 9 = 12285 N
Difference in force = 12285 - 12150 = 135 N (towards the second team as it has more force)
(a) For acceleration we get:
F = m * a
135 = (mass of both teams) * a
a = 135 / (612 + 657)
acceleration = 0.1063 m/s^2 (Second team wins)
(b) Since we know the acceleration of the first team (pulling being pulled towards the second team at an acceleration of 0.1063 m/s^2) , we can find out the force required to move them:
Force required for first team = mass of first team * acceleration
Force required = 612 * 0.1063
Force required = 65.106 N
This is the force exerted on the first team through the rope, so the tension in the rope will also be 65.106 N.