Answer:
(240 × 3 × 31.998)/(122.5 × 2) g
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 122.5 31.998
2KClO₃ ⟶ 2KCl + 3O₂
Mass/g: 240
Mass of O₂ = 240 g KClO₃ × (1 mol KClO₃/122.5 g KClO₃) × (3 mol O₂/2 mol KClO₃) × (31.998 g O₂/1 mol O₂) = 94.0 g O₂
Mass of O₂= (240 × 3 × 31.998)/(2 × 122.5) = 94.0 g O₂
This is a D. combustion reaction
That is because you add O2 which is necessary for a combustion, while the results are CO2 and water. What you are missing is a ---> after the 2O2 (g)
Answer : The number of molecules present in nitrogen gas are,
Explanation :
First we have to calculate the moles of nitrogen gas by using ideal gas equation.
where,
P = Pressure of
gas =
(1 atm = 760 mmHg)
V = Volume of
gas = 985 mL = 0.982 L (1 L = 1000 mL)
n = number of moles
= ?
R = Gas constant =
T = Temperature of
gas =
Now put all the given values in above equation, we get:

Now we have to calculate the number of molecules present in nitrogen gas.
As we know that 1 mole of substance contains
number of molecules.
As, 1 mole of
gas contains
number of molecules
So,
mole of
gas contains
number of molecules
Therefore, the number of molecules present in nitrogen gas are,
Answer: atoms do have 3 subatomic particles but the nucleus is positive and the nucleus consists of protons and neutrons. Its positive because neutrons have no charge and protons have a positive charge. There are only electrons on the shells so no neutrons or protons on the shells
Explanation: