Alright, so this question covers the subject of spontaneous reactions. Reactions tend to be spontaneous if the products have a lower potential energy than the reactants or when the product molecules are less ordered than the reactant molecules. This may seem a little confusing but to put it simply, spontaneous reactions occur naturally.
This means there is no external force for the reaction, usually exothermic, and increases entropy. Gibbs free energy change helps us determine if the reaction is spontaneous:
delta G= delta H -T(delta S) spontaneous if delta G<0
Remember that H stands for enthalpy, or potential energy; T is for temperature; and S is entropy, the amount of disorder(spontaneous reactions increase in entropy take for ice to liquid water).
- delta H= exothermic
The reaction in the problem releases heat so the enthalpy is negative.
delta S increases with increased temperature
The entropy will be positive.
Plugging this in the Gibbs equation, you can assume delta G will be less than 0.
Therefore, the answer is B. Sorry for the long and possibly not helpful explanation. I'm learning this material currently myself. Best of luck!
Answer:
The answer to your question is: 2.20 x 10 ²³ molecules
Explanation:
Data
mass = 45.7 g
molecules of CF₂Cl₂ = ?
Process
1.- Calculate the mass number of CF₂Cl₂
C = 12 F =2 x 19 Cl = 2 x 35.5
total = 12 + 38 + 71
total = 121 g
2.- Use the Avogradro's number to solve the problem
121 g ------------------- 6.023 x 10²³ molecules of CF₂Cl₂
45.7 g --------------- x
x = (45.7 x 6.023 x 10²³) / 121
x = 2.75 x 10²⁵ / 121
x = 2.20 x 10 ²³ molecules
Answer:
49.8cm
Explanation:
hope it helps i even double checked for you :D
Answer:
A safety guide lines are rules and regulations that are made to make sure place is safe and conducive for everyone.
Answer:
430 kPa
Explanation:
Use the formula PV/T = PV/T where the left side of the equation refers to the initial values and the right side refers to the final values: (170.2 kPa)(3.5 L)/(298 K) = (P)(1.35 L)/(293 K). The P represents the unknown pressure. Solving this equation gives us a value for P of 433.855 kPa, but because of significant figures (the two from 3.5 L), we round to 430 kPa.
