Question

Enter your answer in the provided box. Consider the reaction: N2(g) + 3H2(g) → 2NH3(g) Suppose that a particular moment during the reaction, molecular hydrogen is reacting with a magnitude of 0.0759 M/s. At what rate is molecular nitrogen reacting?

Answer 1

Answer:

0.0253 M/s

Explanation:

From the reaction

N₂ + 3H₂ → 2NH₃

The rate of reaction can be written as

Rate = - $\frac{d[N_2]}{dt}$ = - $\frac{1}{3} \frac{d[H_2]}{dt}$ = + $\frac{1}{2} \frac{d[NH_3]}{dt}$

From the above rate equation we can conclude that the rate of reaction of N₂ is equal to one third of the rate of reaction of H₂,

So,

Rate of reaction of molecular nitrogen = $\frac{1}{3} \times 0.0759$

Upon calculation, we get rate of reaction of molecular nitrogen = 0.0253 M/s