The products obtained from the dissociation of HNO₃ in water are hydronium ion, H₃O⁺ and nitrate ion, NO₃¯
An acid is a substance which when dissolved in water produces hydronium ion, H₃O⁺ as the only positive ion.
Strong acid ionize completely in water while weak acid only ionize to a certain degree (i.e partially) in water
Trioxonitrate (v) acid, HNO₃ is a strong acid and will ionize complete in water to form hydronium ion, H₃O⁺ and nitrate ion, NO₃¯ as illustrated below:
HNO₃ + H₂O —> H₃O⁺ + NO₃¯
Thus, the products for the dissociation equation are: hydronium ion, H₃O⁺ and nitrate ion, NO₃¯
Learn more: brainly.com/question/13173940
Answer:
= 49.674 g NaCl
Explanation:
From the equation;
1 mole of Sodium metal produces 2 moles sodium chloride
This means;
23 g of Na will produce 116.88 g of NaCl
Therefore;
11.5 g will generate;
= (11.5 × 116.88)/23
= 58.44 g of NaCl
But;
Percentage yield = (Actual yield/Theoretical yield)× 100%
85 /100 = Actual yield /58.44 g
Thus;
Actual yield = 0.85 × 58.44
= 49.674 g NaCl
Because the valence shell of gases wants to become full
Answer:
473 year
Explanation:
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
Given:
To reach 12.5% of reactant means that 0.125 of is decomposed. So,
![\frac {[A_t]}{[A_0]}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D)
= 0.125
t = ?
![\frac {[A_t]}{[A_0]}=e^{-k\times t}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%3De%5E%7B-k%5Ctimes%20t%7D)
t = 473 year
