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AlladinOne [14]
3 years ago
8

Water _____.

Chemistry
1 answer:
Sergio039 [100]3 years ago
4 0

Answer: is neither an acid nor a base

Explanation: Water is a universal solvent which means it can dissolve most of the substances in it.

Water has high thermal heat capacity , which means large heat is required to heat the water.

Water is not always pure as it gets contaminated by various pollutants present in the atmosphere such as gases, bacteria and suspended matter.

Water is an amphoteric substance which can act as both acid and base, thus can donate and acept [texH^+[/tex] ions.Thus it is neither an acid nor a base.

HCl+H_2O\rightarrow H_3O^++Cl^-

Here water is accepting a proton, thus it acts as base.

NH_3+H_2O\rightarrow NH_4^++OH^-

Here water is donating a proton, thus it acts as acid.




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A) gases; solids
B) metals; nonmetals
C) nonmetals; metals
<span>D) reactive; nonreactive
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I think the correct answer is option B. The stair-step line between the pink squares and the yellow squares separates the metals from the nonmetals. Hope this helps.
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Principle quantum number.

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You are given solutions of hcl and naoh and must determine their concentrations. you use 27.5 ml of naoh to titrate 100.0 ml of
Dafna1 [17]
1) Start by standardizing the solution of NaOH by using the solution of H2SO4 whose concentration is known.

2) Equation:

2Na OH + H2SO4 --> Na2 SO4 + 2H2O

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2 mol NaOH : 1 mol H2SO4

4) Number of moles of H2SO4 in 50.0 ml of 0.0782 M solution

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5) Number of moles of NaOH

2 moles NaOH / 1mol H2SO4 * 0.00391 mol H2SO4 = 0.00782 mol NaOH

6) Concentration of the solution of NaOH

M = n / V = 0.00782 mol / 0.0184 ml = 0.425 M

7) Standardize the solution of HCl

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NaOH + HCl --> NaCl + H2O

8) Molar ratios

1 mol NaOH : 1 mol HCl

9) Number of moles of NaOH in 27.5 ml

M = n / V => n = M * V = 0.425 M * 0.0275 l = 0.01169 moles NaOH

10) Number of moles of HCl

1 mol HCl / 1mol NaOH * 0.01169 mol NaOH = 0.01169 mol HCl

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Answers:

[NaOH] = 0.425 M
[HCl] = 0.117 M
3 0
3 years ago
The table describes how some substances were formed.
gogolik [260]

Answer:

Formed by adding 5 g of sugar to 1 L of water

Explanation:

The substance formed by adding 5 g of suagr to 1 L of water is a mixture.

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The products formed from other descriptions in the illustration cannot be separated ordinarily and thus, are not considered to be mixture. The components have been chemically combined together.

6 0
3 years ago
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