Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
Answer:
Explanation:
The following code is written in Python. It asks the user for an input. Then cleans the input using regex to remove all commas, whitespace, and apostrophes as well as making it all lowercase. Then it reverses the phrase and saves it to a variable called reverse. Finally, it compares the two versions of the phrase, if they are equal it prints out that it is a palindrome, otherwise it prints that it is not a palindrome. The test case output can be seen in the attached picture below.
import re
phrase = input("Enter word or phrase: ")
phrase = re.sub("[,'\s]", '', phrase).lower()
reverse = phrase[::-1]
if phrase == reverse:
print("This word/phrase is a palindrome")
else:
print("This word/phrase is NOT a palindrome")
1. <span>The Joint Photographic Experts Group developed the jpeg graphic format.
2. </span><span>It is important to include the alt attribute of the tag because some people use text-only Web browsers. </span>
Answer:
The answer to this question is True.
Explanation:
If we allow every communication this will not be a great idea if we want better security and better productivity.
There will be a lot of spam communications so the productivity and the security will also degrade because of that.
So if we want better productivity and security we have to allow a certain number of connections.
Hence the answer to this question is True.
Answer:
public class Brainly
{
public static void main(String[] args)
{
BinaryConverter conv = new BinaryConverter();
String binStr = "01001101";
System.out.print(binStr + " in decimal is "+conv.BinToDec(binStr));
}
}
public class BinaryConverter
{
public int BinToDec(String binStr)
{
int d = 0;
while(binStr.length() > 0)
{
d = (d << 1) + ((binStr.charAt(0) == '1') ? 1: 0);
binStr = binStr.substring(1);
}
return d;
}
}
Explanation:
The program "eats" the string from left to right, and builds up the integer representation in variable "d" on the go. While there are digits left, it shifts the previous result to the left and sets the least signficant bit to 1 only if the corresponding string character is a 1.
