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lora16 [44]
3 years ago
10

Write in simplest form 17 1/2 +3 5/6

Mathematics
1 answer:
Vlad [161]3 years ago
3 0

17 \frac{1}{2}  + 3 \frac{5}{6}  + 3 \frac{5}{6}
\frac{35}{2}  + 3 \frac{5}{6}
\frac{35}{2}  +  \frac{23}{6}
\frac{64}{3}
ANSWER
21 \frac{1}{3}

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kicyunya [14]
Hello!

Your answer is \frac{23}{99}

If you use a calculator and divide 23 by 99, you will get 0.232323............

Answer ⇒ \frac{23}{99}
8 0
3 years ago
What is x in the equation x+3=9
densk [106]

Answer:

x=6

Step-by-step explanation:

x+3=9

x+3-3=9-3

x=6

5 0
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Leokris [45]

Answer:

C

Step-by-step explanation:

7 0
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Cna i get some help with dis plz
Tomtit [17]

Let b_1,b_2,\ldots,b_{20} be the 20 marks of the boys, and g_1,g_2,\ldots,g_{10} be the 10 marks of the girls.

We know that the global mean was 70, meaning that

\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70

Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is

b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100

By the same logic, we work with the marks of the boys alone: we know the average:

\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62

And we deduce the sum of the marks for the boys:

b_1+b_2+\ldots+b_{20}=1240

Which implies that the sum of the marks of the girls is 2100-1240=860

And finally, the mean for the girls alone is

\dfrac{860}{10}=86

6 0
3 years ago
Georgianna claims that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.
Allisa [31]

Answer:

The  condition  are

           The  Null hypothesis is  H_o  :  \mu = 5

           The  Alternative hypothesis is  H_a  :  \mu <  5

The  check revealed that

             There is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons

Step-by-step explanation:

From the question we are told that

     The  population mean is  \mu =  5 \ year

      The sample size is  n =  20

      The sample mean is  \=  x  =  4.6 \  years

       The  standard deviation is \sigma  =  2.2  \ years

   The  Null hypothesis is  H_o  :  \mu = 5

   The  Alternative hypothesis is  H_a  :  \mu <  5

So i will be making use of  \alpha =  0.05 level of significance to test this claim

    The critical value of  \alpha from the normal distribution table is  Z_\alpha  =  1.645

 

Generally the test statistics is mathematically evaluated as

                 t =  \frac{\= x  - \mu}{ \frac{\sigma }{\sqrt{n} } }

substituting values

                 t =  \frac{ 4.6  - 5}{ \frac{2.2}{\sqrt{20} } }

                t =  -0.8131

Looking at the value of  t and Z_{\alpha } we see that  t <  Z_{\alpha } so we fail to reject the null hypothesis  

  This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

4 0
3 years ago
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