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Rudiy27
3 years ago
14

A fish is removed from a contaminated lake. You determine that a particular toxin (X) is present in its cells at concentration X

= 1,500 μg/L. You place the fish in a tank full of clean water (X = 0 μg/L), and measure the toxin concentration in the fish cells each day for the next 10 days.
After making your hypothesis, you test it by measuring the toxin levels in the fish at various times during its 10 days in the tank. You observe that the level of toxin in the fish drops from 1,500 μg/L to 750 μg/L and then stabilizes at 750 μg/L. You test the water in the tank and find that after it stabilizes, toxin is present in the water at concentration 750 μg/L also. What can you do to continue to reduce the toxin level in the fish below 750 μg/L?
Chemistry
1 answer:
netineya [11]3 years ago
3 0
The level of toxins in the fish's cell is equivalent to the level of toxins in the water. Therefore, in order to reduce the toxins further, we should replace the now contaminated water with clean water. After the level of toxins in the fish's cell stops reducing, we replace the water with clean water once again.
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IgorLugansk [536]

Answer:

18 km

Explanation:

To know the distance, you need to be clear in the concept of distance.

According to the physics, the distance is a measurement that refers to the fact of how much an object has move from one point to another.

In this case, we have a person named Steve and he's walking through several points.

To calculate the distance that he moved, you just need to sum all the values of distance. In this case, it's not neccesary to do calculations regarding the components of the x or y axis, because we are not talking about displacement, where it actually counts. But in this case, we just need all the covered distance that Steven walked since the beggining.

So, no more talk, let's do calculations:

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3 years ago
How many minutes are in 180,0 days?
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So, you should take the first three numbers of the answer:

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8 0
3 years ago
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