Answer:
-470.4 kJ/mol
Explanation:
Balanced reactions equations are as follows.
CaC2 (s) + 2H2O (l) â C2H2 (g) + CaOH2 (s) ÎH=â414.kJ
6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ
To get the 6 C2H2 we need to multiply first equation by 6
Then we get
6CaC2 (s) + 12H2O (l) â 6C2H2 (g) + 6CaOH2 (s) ÎH=â414.kJ * 6 = -2484 kJ
6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ
So the total energy produced = -2484 kJ + 132.0 kJ = -2352 kJ
This amount of energy is given out for the 5 moles of acid
So lets convert it for 1 mol
-2352 kJ * 1 mol / 5 mol = -470.4 kJ/mol
So the delta H of reaction for the formation of the acrylic acid is -470.4 kJ/mol
