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elena-14-01-66 [18.8K]
3 years ago
9

What is the formula of the compound formed between the potassium ion and the sulfide ion?

Chemistry
1 answer:
KIM [24]3 years ago
4 0
The formula for K+ and S-2 is K2S because you need 2 potassium ions to balance out the sulfide ion
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the quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dis
Basile [38]

Answer:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

Explanation:

At a redox equation, one substance is being oxidized (losing electrons), and the other is being reduced (gaining electrons). In the given reaction:

BrO₃⁻(aq) + Sb³⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq)

When it's at an acidic solution, it must be ions H⁺ on the reactant, which will form water with the oxygen, so the complete reaction is:

BrO₃⁻(aq) + Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq) + H₂O(l)

As we can see, the antimony is being oxidized (go from +3 to +5), and the Bromo is being reduced. The oxidation number of brome in the reactant, knowing that the oxidation number of O is -2, is:

x + 3*(-2) = -1

x = +5

So, it's going from +5 to -1, and the half-reactions are:

BrO₃⁻(aq) + 6e⁻ → Br⁻(aq)

Sb³⁺(aq) → Sb⁵⁺(aq) + 2e⁻

The number of electrons must be the same, so the second equation must be multiplied by 3:

3Sb³⁺(aq) → 3Sb⁵⁺(aq) + 6e⁻

Thus, the equation will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + H₂O(l)

Now, we verify the amount of the elements, which must be equal on both sides. So, we multiply H₂O by 3, and H⁺ by 6, and the balanced reaction will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

6 0
3 years ago
What is the temperature (in K) of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?
AlexFokin [52]
Using the ideal gas law: PV=nRT
      P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.

(4.68)*(4.95)=(16.45)*(0.0821)*T
Solve for T. 
T=17.15
4 0
3 years ago
A gas at 65°C occupies 4.0 L. At what temperature will the volume be 3.0 L?
Serjik [45]

Answer:

253.5 K

Explanation:

Charles law equation, which is as follows is used to solve this question:

V1/T1 = V2/T2

Where;

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the numerical information provided in this question:

V1 = 4.0 L

V2 = 3.0 L

T1 = 65°C = 65 + 273 = 338K

T2 = ?

Using V1/T1 = V2/T2

V1T2 = V2T1

T2 = V2 × T1/V1

T2 = 3 × 338/4

T2 = 1014/4

T2 = 253.5 K

4 0
3 years ago
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