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elena-14-01-66 [18.8K]
3 years ago
9

What is the formula of the compound formed between the potassium ion and the sulfide ion?

Chemistry
1 answer:
KIM [24]3 years ago
4 0
The formula for K+ and S-2 is K2S because you need 2 potassium ions to balance out the sulfide ion
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Nhóm axit nào tác dụng với mg tạo ra h2o
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2 years ago
If the volume occupied by 0.500 mol of nitrogen gas at 0°C is 11.2 L, then the volume occupied by 2.00 mol of nitrogen gas at th
Paraphin [41]
Avagadros law states that volume of gas is directly proportional to number of moles of gas at constant pressure and temperature.
\frac{V1}{n1} =  \frac{V2}{n2}
where V -volume , n - number of moles 
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
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5 0
3 years ago
N which block of the periodic table is uranium (U) found?
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4 0
3 years ago
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Select all of the following equations that represent an exothermic reaction.
skelet666 [1.2K]
Exothermic reactions:

1)  release heat to the surroundings

2) the change of enthalpy, ΔH, is negative: ΔH < 0

3) the temperature of the system increases

With that you can conclude about every equation given:

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3 0
3 years ago
how many atoms of gold are present in 0.6 gm of 18 caral gold? ( 24 caral gold in 100% pure) atomic weight of gold = 197?​
julsineya [31]

Answer:

<h2>HERE'S YOUR ANSWER </h2>

We are given that the ring is made up of 20 carrat gold. 20 carrat gold means 20 parts of gold and 4 parts of other metal (usually copper or silver). Thus, the percentage of gold in 20 carrat gold will be

= (20 / 24) X 100

= 83.333 %

We can now calculate the mass of gold in the ring. We are given that the ring weighs 300 mg. So, the mass of gold in ring will be

= (83.333 / 100) X 300

= 250 mg

Thus, the mass of gold in 300 mg of the ring is 250 mg.

Now the molar mass of gold is 197 g. This means that there are 6.023 X 1023 atoms of gold in 197g of gold. Thus

197g of gold = 6.023 X 1023 atoms of gold

1g of gold = (6.023 X 1023 ) / 197 atoms of gold

250 mg or 0.25g of gold = (6.023 X 1023 X 0.25) / 197 atoms of gold

= 7.643 X 1020 atoms of gold

<h2>HOPE IT HELPS MAN ☺️</h2>

3 0
2 years ago
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