Whats 67/8 simplified

Mathematics

2 answers:

DochEvi [55]3 years ago

7 0

Answer:

8.375 or 8 3/8

IrinaVladis [17]3 years ago

4 0

Answer:

8 3/8

Step-by-step explanation:

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You are planning to make a collage and are gathering materials.for the backing you will use a piece of heavy recycled cardboard

Lunna [17]

1. 4 3/4 feet = 19/4 feet
2 2/5 feet=12/5 feet.
multiplying them together yields
$\frac{19}{4} * \frac{12}{5} =$
$= \frac{57}{5} = 11.4 ft^{2}$

Part 2:
11.4 ft^2 - 4 1/2 ft^2=
11.4-4.5=6.9 ft^2 = 69/10 ft^2 left after you subtract the decoration in the middle
Now you're trying to find now many rectangular cutouts (that each are 3/8 ft^2) will fit in the remaining space.
You do that by dividing the remaining space left by 3/8:
$\frac{69}{10} / \frac{3}{8} = \frac{69}{10} * \frac{8}{3} = \frac{92}{5}$
since you have to have a whole number of cutouts, you round 92/5 down to 90/5, which is 18 cutouts

5 0

3 years ago

Plz, help ASAP!!! WILL MARK YOU BRAINLIEST IF UR ANSWER IS CORRECT QUESTION #5

bija089 [108]

Answer:

Step-by-step explanation:

The domain remains the same [a, b) and the range is [mc + n,md + n).

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3 years ago

Nancy has nine books and she has read 8 total books Sally has two times more books the Nancy how many books does Sally have

ankoles [38]

Sally has eight-teen books.

7 0

4 years ago

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t)

beks73 [17]

H(t) = Ho +Vot - gt^2/2

Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2

H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2

Maximun height is at the vertex of the parabole

To find the vertex, first find the roots.

58.8 + 19.6t - 4.9t^2 = 0

Divide by 4.9

12 + 4t - t^2 = 0

Change sign and reorder

t^2 - 4t -12 = 0

Factor

(t - 6)(t + 2) =0 ==> t = 6 and t = -2.

The vertex is in the mid point between both roots

Find H(t) for: t = [6 - 2]/2 =4/2 = 2

Find H(t) for t = 2

H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4

Answer: the maximum height is 78.4 m

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3 years ago

The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp

Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .