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gavmur [86]
3 years ago
11

What is the volume of the square pyramid?

Mathematics
2 answers:
slega [8]3 years ago
6 0
The volume of the square pyramid equals :
Base x heigth = (7*7)*9=441 cm³
Lubov Fominskaja [6]3 years ago
3 0
The volume of the square pyramid is 147 centimeters.
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George is solving the equation below by finding successive approximations. He started from a graph where he found the solution t
skelet666 [1.2K]

The mistake made by George is; D:George should have averaged the two differences instead of the two bounds.

<h3>How to Solve Successive Approximations?</h3>

In Mathematics, successive approximation can be defined as a classical method that is used in Calculus for solving integral equations or initial value problems.

In this question, George started the first iteration of successive approximation by using the lower and upper bounds of the graph. However, we can deduce that George made a mistake instep 5 because he should have used x = 3/2 as the new upper bound.

Read more about Successive Approximations at; brainly.com/question/25219621

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6 0
2 years ago
Find the solution to the equation below.
Andreyy89

Answer:

B and D

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=20, b=-26, and c=8.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{26+/-\sqrt{26^2-4(20)(8)} }{2(20)}=\frac{26+/-\sqrt{676-640} }{40)}

\frac{26+/-\sqrt{36} }{40}=\frac{26+/-6 }{40}

This means the solutions are 26 - 6/ 40 and 26 + 6/ 40.

It simplifies to 1/2 and 4/5.

3 0
3 years ago
How do I do this problem
STatiana [176]

Answer:

shape one would have to move 8 units to the right and 5 units down and then flip

i hope this helped you to understand more

Step-by-step explanation:

3 0
3 years ago
Find the horizontal asymptote of the graph
sleet_krkn [62]

y = -  \frac{1}{2}
5 0
3 years ago
Read 2 more answers
If angle X is an acute angle with tan X = 8/7, what is the value of sec X?
iren [92.7K]

Answer: \frac{\sqrt{113}}{7}

Step-by-step explanation:

As X is an acute angle, all 6 trigonometric functions with an argument of X are positive.

Using the identity 1+\tan^{2} X=\sec^{2} X,

1+\left(\frac{8}{7} \right)^{2}=\sec^{2} X\\\\\sec^{2} X=\frac{113}{49}\\\\\therefore \sec X=\boxed{\frac{\sqrt{113}}{7}}

5 0
1 year ago
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