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777dan777 [17]
3 years ago
15

The compressor on an air conditioner draws 121 A when it starts up. The start-up time is about 0.505 s. How much charge passes a

cross-sectional area of the circuit in this time?
Physics
1 answer:
attashe74 [19]3 years ago
4 0

Answer:

61.105 C

Explanation:

Charge: This can be defined as the product of current flowing through a circuit and time. The S.I unit of charge is coulomb's (C)

I = Q/t ................. Equation 1

Where I = current, Q = Charge, t = time.

Note: The current through a cross sectional area of the compressor is the amount of charge passing through the area per unit time.

Q = It ............... Equation 2

Given: I = 121 A, t = 0.505 A.

Substitute into equation 2

Q = 121(0.505)

Q = 61.105 C.

Hence the charge passing through the cross sectional area of the circuit = 61.105 C

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Answer:

4 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')...................... Equation 1

Where m = mass of the arrow, u = initial velocity of the arrow, m' = mass of the apple, u' = initial velocity of the apple, V = Final velocity of the apple and the arrow after collision.

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V = (mu+m'u')/(m+m').................... Equation 2

Given: m = 0.5 kg, m' = 2 kg, u = 20 m/s, u' = 0 m/s(initially at rest)

Substitute into equation 2

V = (0.5×20+2×0)/(2+0.5)

V = 10/2.5

V = 4 m/s.

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6 0
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Answer:

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Fk = μFn

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Substituting into the equation, we have;

Fk = 0.2*30

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