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Artist 52 [7]
3 years ago
15

In moving out of a dormitory at the end of the semester, a student does 1.82 x 104 J of work. In the process, his internal energ

y decreases by 4.07 x 104 J.
Determine each of the following quantities (including the algebraic sign):

(a)W,

(b)U

(c)Q.
Physics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

Explanation:

(a) Work done, W = 1.82 x 10^4 J

(b) internal energy, U = - 4.07 x 10^4 J ( as it decreases)

(c) According to the first law of thermodynamics  

Q = W + U

Q = 1.82 x 10^4 - 4.07 x 10^4

Q = - 2.25 x 10^4 J

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olga nikolaevna [1]

Answer:

The magnetic flux density is 2.11\times10^{-6}\ T

Explanation:

Given that,

Distance = 0.36 m

Current = 3.8 A

We need to calculate the magnetic flux density

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B =\dfrac{\mu_{0}I}{2r}

Where,

r = radius

I = current

Put the value into the formula

B =\dfrac{4\pi\times10^{-7}\times3.8}{2\times\pi\times0.36}

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3 years ago
What does the scientific method help test in environmental science?
Hatshy [7]

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The scientific method helps test and arrive at conclusions for a variety of hypotheses that are created when studying environmental science.

Explanation:

What is the scientific method in environmental science?

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5 0
3 years ago
A mover uses a ramp to load a crate of nails onto a truck. The crate, which must be lifted 1.5 m from the street to the bed of t
jonny [76]

Answer:

<h2>3</h2>

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Distance moved by effort = 4.5m

distance moved by load = 1.5m

VR = 4.5/1.5 =3

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1 = MA/3

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A 4.2-m-diameter merry-go-round is rotating freely with an angularvelocity of 0.80 rad/s. Its total moment of inertia is1760kgm2
ASHA 777 [7]

Answer

given,

mass of people = 65 kg

number of people =

diameter of the  merry-go-round = 4.2 m

radius = 2.1 m

angular velocity = 0.8 rad/s

moment of inertia =  1760 kg m²

Using the law of conservation of angular momentum, we have

                             L₁=  L₂

                          I₁ω₁ =I₂ω₂

                            I₁ω₁= ( I₁+ 4 m r²)ω²

                         ( 1760 x 0.8) = ( 1760 + 4 x 65 x 2.12)ω²

                         1408 = 2311.2 ω²

                         ω² = 0.609

                         ω  = 0.781 rad/s

b) If the people jump of the merry-go-round radially, they exert no torque.

hence,  it will not change the angular momentum of the merry-go-round. It will continue to move with the same   ω .

7 0
3 years ago
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