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LiRa [457]
3 years ago
15

Can you answer the first question for me

Mathematics
2 answers:
loris [4]3 years ago
5 0
All are true except d 
Lera25 [3.4K]3 years ago
5 0
1
a) yes
b) yes
c) yes
d) yes
e) no
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Which of the following is a multiple of 5
jok3333 [9.3K]
10 15 20 25 30....etc hope this helps you!!
6 0
2 years ago
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I am thinking of two numbers. The sum of the numbers is 5. The first number is one less than the second number. Write a system o
Dominik [7]

Answer:

x + y = 5

y = x - 1

Hope this helped!

7 0
2 years ago
F(x)=tan(x)
AleksAgata [21]
<span>Tan(x) = sin(x) / cos(x). Therefore, tan(x) pi/2 = 1/0, which doesn't exist. Imagine that, instead of 0, it's a number incredibly close to 0. The smaller the number in the denominator, the bigger the outcome. Therefore, we can think of 1/0 as infinity, or approaching infinity as one gets closer to 1/0. This is the same result approaching from the negative side, only it's negative infinity. If x=0, it's 0/1 instead (sin 0=0, cos 0=1). Anything divided by 1 is itself, so as x approaches 0, so does f(x).</span>
7 0
3 years ago
The graph of y=1/x is shown below. Draw the graph of its inverse.
lord [1]
Y=1/x  solve for x

x=1/y  now reverse lables...

y=1/x  

Yes that is the same equation you started with.  What that means is the the inverse function in this case produces the same exact graph :)
4 0
3 years ago
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In the diagram AB=AD and
hammer [34]

Answer:

AC ≅ AE

Step-by-step explanation:

According to the SAS congruence theorem, if two triangles have 2 corresponding sides that are equal, and also have one included corresponding angle that are equal to each other in both triangles, both triangles are regarded as congruent.

Given ∆ABC and ∆ADC in the question above, we are told that segment AB ≅ AD, and also <BAC ≅ <DAC, the additional information that is necessary to prove that ∆ABC and ∆ADC are congruent, according to the SAS theorem, is segment AC ≅ segment AE.

This will satisfy the requirements of the SAS theorem for considering 2 triangles to be equal or congruent.

6 0
2 years ago
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