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2 years ago

Can you answer the first question for me

Mathematics

2 answers:

loris [4]2 years ago

5 0

All are true except d

Lera25 [3.4K]2 years ago

5 0

1
a) yes
b) yes
c) yes
d) yes
e) no

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Pls help It’s due tomorrow question is in the picture

Slav-nsk [51]

Answer:

Step-by-step explanation:

Let's find the area of each of the two circles.

First Circle:

The first circle has a diameter of 10 inches. That means the radius is 5 inches. So, its area is:

$A=\pi r^2\\A=\pi (5)^2\\A=25\pi$

Second Circle:

The second circle has a diameter twice that of the first. So, the diameter is 20 inches. This means that the radius is 10 inches. Find the area:

$A=\pi r^2\\A=\pi (10)^2\\A=100\pi$

Now, find the ratio between them by dividing:

$\frac{\text{Smaller}}{\text{Larger}}=\frac{25\pi}{100\pi}$

Simplify:

$\frac{\text{Smaller}}{\text{Larger}}=\frac{1}{4}$

1/4 is the same as 1:4

So, our answer is C :)

5 0

2 years ago

Gracie bought a cd for $810 that earns a 2.9 APR and is compounded quarterly. The CD matures in 5 years. How much will this CD b

enyata [817]

Answer:

The amount that this CD will be worth at maturity would be $935.90. The right answer is B.

Step-by-step explanation:

In order to calculate How much will this CD be worth at maturity we would have to use and calculate the formula of future value as follows:

Future Value=Present value×(1+i/n)∧nt

Future Value=$810×(1+2.9%/4)∧(4×5)

Future Value=$935.90

The amount that this CD will be worth at maturity would be $935.90

8 0

3 years ago

Please help me guys

Marianna [84]

If you multiply $60 by 0.15 you'll get 9 which is the taxes of the meal. Since he leaves the same percentage of tip, now we add 9+9 and get $18..
60+18=78

6 0

2 years ago

The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?

adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)$

$\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}$

$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$

3 0

1 year ago

Can someone help? 25 points

denpristay [2]

Answer:

the answer is 157

Step-by-step explanation:

i had a test with the same question, i promise its right :)

7 0

2 years ago