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kupik [55]
4 years ago
8

Which Group is in the second column of the periodic table?

Chemistry
1 answer:
WINSTONCH [101]4 years ago
8 0

Answer:

alkaline

Explanation:

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If a 22.4 L volume of a sample of gas has a density of 0.900 grams/L at 1.00 atm and 0.00°C. Given
disa [49]

Answer:

Formula Weight of gas sample = 20.1 g/mole => Neon (Ne)

Explanation:

Use Ideal Gas Law formula to determine formula weight and compare to formula weights of answer choices.

PV = nRT = (mass/fwt)RT => fwt = (mass/Volume)RT = Density x R x T

Density = 0.900 grams/L

R = 0.08206 L·atm/mole·K

T = 0.00°C = 273Kfwt = (0.900g/L)(0.08206L·atm/mole·K )(273K)

= 20.1 g/mol => Neon (Ne)

4 0
3 years ago
The hydrogen ion​ concentration, ​[H+​], in a certain cleaning compound is left bracket Upper H Superscript plus Baseline right
labwork [276]

<u>Answer:</u> The pH of the cleaning compound is 10.44

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen or hydronium ion concentration that are present in a solution.

The equation representing pH of the solution follows:

pH=-\log[H^+]

We are given:

[H^+]=3.6\times 10^{-11}

Putting values in above equation, we get:

pH=-\log(3.6\times 10^{-11})

pH=10.44

Hence, the pH of the cleaning compound is 10.44

8 0
3 years ago
What is the empirical formula of a hydrocarbon if complete combustion or 2.900 mg of the hydrocarbon produced 9.803 mg of CO2 an
kow [346]

Answer:

The empirical formula of the hydrocarbon is CH.

Explanation:

The following data were obtained from the question:

Mass of hydrocarbon = 2.9 mg

Mass of CO2 = 9.803 mg

Mass of H2O = 2.006 mg

Next, we shall determine the mass of carbon (C) and hydrogen (H) in the compound since hydrocarbon contains carbon and hydrogen only.

This is illustrated below:

Molar mass of CO2 = 12 + (16x2) = 12 + 32 = 44 g/mol

Mass of CO2 = 9.803 mg

Mass of C in the compound =?

Mass of C in the compound =

12/44 x 9.803

= 2.674 mg

Molar mass of H2O = (2x1) + 16 = 2 + 16 = 18 g/mol

Mass of H2O = 2.006 mg

Mass of H in the compound =

2/18 x 2.006

= 0.223 mg

Finally, we shall determine the empirical formula of the hydrocarbon as follow:

Carbon (C) = 2.674 mg

Hydrogen (H) = 0.223 mg

Divide by their molar mass

C = 2.674 /12 = 0.223

H = 0.223 / 1 = 0.223

Divide both side by the the smallest

C = 0.223/0.223 = 1

H = 0.223/0.223 = 1

Therefore, the empirical formula of the hydrocarbon is CH.

5 0
3 years ago
Oops i dont think i meant to do this
Delicious77 [7]

Answer:

Bro the paw patrol movie is amazing

Explanation:

7 0
3 years ago
Read 2 more answers
What is the empirical formula of a compound that contains 27.0% s, 13.4% o, and 59.6% cl by mass?
Bezzdna [24]
27g of 's × 1 mole/32.065g equals 0.84
13.4g of o × 1 mole/16g equals 0.83
Divide all these by the smallest number then round to the nearest number.
6 0
4 years ago
Read 2 more answers
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