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AlladinOne [14]
3 years ago
12

CuSO4 . 5H2O is dehydrated to form Copper (ii) sulfate. Is this a physical or chemical change? Explain.

Chemistry
1 answer:
Paraphin [41]3 years ago
3 0

Answer:

It is a physical change.

Explanation:

• This is because when anhydrated copper (ii) sulfate is heated, the water evaporates to form anhydrous copper (ii) sulfate.

• evaporation is a physical change

.

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The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:
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Answer:

Enthalpy change for the reaction is -67716 J/mol.

Explanation:

Number of moles of AgNO_{3} in 50.0 mL of 0.100 M of AgNO_{3}

= Number of moles of HCl in 50.0 mL of 0.100 M of HCl

= \frac{0.100}{1000}\times 50.0 moles

= 0.00500 moles

According to balanced equation, 1 mol of AgNO_{3} reacts with 1 mol of HCl to form 1 mol of AgCl.

So, 0.00500 moles of AgNO_{3} react with 0.00500 moles of HCl to form 0.00500 moles of AgCl

Total volume of solution = (50.0+50.0) mL = 100.0 mL

So, mass of solution = (100.0\times 1.00) g = 100 g

Enthalpy change for the reaction = -(heat released during reaction)/(number of moles of AgCl formed)

= \frac{-m_{solution}\times C_{solution}\times \Delta T_{solution}}{0.00500mol}

= \frac{-100g\times 4.18\frac{J}{g.^{0}\textrm{C}}\times [24.21-23.40]^{0}\textrm{C}}{0.00500mol}

= -67716 J/mol

[m = mass, c = specific heat capacity, \Delta T = change in temperature and negative sign is included as it is an exothermic reaction]

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Explanation:

think its specific heat of water = 4.18 J/g°Ci

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