Answer:
) You must create a Low Pass Filter for an audio amplifier. You must pass 10khz and block
60khz. In designing this, you must choose a cutoff frequency exactly half way between
these two frequencies. In addition, you must use a 0.2uF capacitor in you LPF circuit.
Given these criteria, analyze this circuit, and determine the necessary resistor value in
Ohms. Find the output Voltage at both ends of the spectrum. Based on your results, is
this a good design? NOTE: You MUST show your work (when using MS Word, choose
“Insert”--- “Equation”). (6 marks)
a. Solve for fc
b. Solve for R
c. Solve for Vout at 10khz
d. Solve for Vout at 60khz
e. Good design> (yes or no with an explanation)
Explanation:
Answer: N has to be lesser than or equal to 1666.
Explanation:
Cost of parts N in FPGA = $15N
Cost of parts N in gate array = $3N + $20000
Cost of parts N in standard cell = $1N + $100000
So,
15N < 3N + 20000 lets say this is equation 1
(cost of FPGA lesser than that of gate array)
Also. 15N < 1N + 100000 lets say this is equation 2
(cost of FPGA lesser than that of standardcell)
Now
From equation 1
12N < 20000
N < 1666.67
From equation 2
14N < 100000
N < 7142.85
AT the same time, Both conditions must hold true
So N <= 1666 (Since N has to be an integer)
N has to be lesser than or equal to 1666.
Answer:
Final mass of Argon= 2.46 kg
Explanation:
Initial mass of Argon gas ( M1 ) = 4 kg
P1 = 450 kPa
T1 = 30°C = 303 K
P2 = 200 kPa
k ( specific heat ratio of Argon ) = 1.667
assuming a reversible adiabatic process
<u>Calculate the value of the M2 </u>
Applying ideal gas equation ( PV = mRT )
P₁V / P₂V = m₁ RT₁ / m₂ RT₂
hence : m2 = P₂T₁ / P₁T₂ * m₁
= (200 * 303 ) / (450 * 219 ) * 4
= 2.46 kg
<em>Note: Calculation for T2 is attached below</em>
Answer:
411.953 kpa
Explanation:
We have the following assumptions
1. Steady incompressible flow.
2. Burst section water pressure = water main pressure
3. Air and water have negligible friction between them.
Max height = 42 m
Max water density = 277.14k
Density of water
Pwater = 999.8395kg/m
Water gets to 42m because of pressure in the line
P (line) = Pwater * g * h
= 999.8395 x 9.81 x 42
= 411.953Kpa
Answer :
6 feet
Explanation :
Outlets can be installed at whatever height,this is comfortable for the intended use. The only NEC requirement is that it must be within 6 feet of an outlet along any wall as this what is tenable (12' between outlets, An unbroken wall space of 2 feet or more including space measured around a corner requires an outlet).