Answer:
the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW
the isentropic pump efficiency is 78%
Explanation:
Given that;
m = 1.2 kg/sec
T = 50 degree Celsius { Vf = 0.001012 m^3/kg}
P1 = 1.5 Mpa
P2 = 15 Mpa
W-actual = 21 kw
W reversible = m*Vf (p2 - p1)
= 1.2 * 0.001012 * ( 15*10^3 - 1.5*10^3)
= 1.2 * 0.001012 * 13500
= 16.39 kW
the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW
Isentropic Pump efficiency = W-reversible / W-actual
= 16.39 / 21 = 0.78
= 78%
the isentropic pump efficiency is 78%
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
The percentage of recycling in high socioeconomic localities is 11.02%.
Explanation:
Since in high socioeconomic localities, 10% of paper is recycled, 12% of plastic, 1.7% of fabrics, 1.2% of rubbers, 0.9% of metals, 3.5% of glass, 33% of food wastes, 35% soil and 1.9% miscellaneous, to determine the average recycling percentage the following calculation must be performed:
(10 + 12 + 1.7 + 1.2 + 0.9 + 3.5 + 33 + 35 + 1.9) / 9 = X
99.2 / 9 = X
11.02 = X
Therefore, the percentage of recycling in high socioeconomic localities is 11.02%.
Answer:
0.39 nM
Explanation:
The critical crack tip radius from the equation
attached below
for fracture to occur the бm will have to reach the fracture strength of material
i.e. бm = E/10
from equation 2 attached below
St = ( 400 * a * бo^2 ) / E^2 ------ 3
Given <em>: a = 2*10^-3 mm , бo = 275 MPa, E = 393 * 10^3 MPa ( gotten from table)</em>
Input given values into equation 3
St = 3.9 * 10^-7 ≈ 0.39 nM