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STALIN [3.7K]
3 years ago
10

A large class with 1,000 students took a quiz consisting of ten questions. To get an A, students needed to get 9 or 10 questions

right. To pass, students needed to get at least 6 questions right. Let X be the number of questions a student got right. The distribution of X is given below. Note: Round all answers to two decimal places when needed.a) If a student is selected randomly from the class, what is the probability he got an A on the quiz?b) How many students got an A on the quiz?c) How many students did not miss a single question on the quiz?d) If a student is selected randomly from the class, what is the probability he passed the quiz?e) How many students passed the quiz?f) How many students failed the quiz?g) If a student is selected randomly from the class, what is the probability that student got at least one question right?

Engineering
1 answer:
VMariaS [17]3 years ago
7 0

Answer:

a. 0.11

b. 110 students

c. 50 students

d. 0.46

e. 460 students

f. 540 students

g. 0.96

Explanation:

(See attachment below)

a. Probability that a student got an A

To get an A, the student needs to get 9 or 10 questions right.

That means we want P(X≥9);

P(X>9) = P(9)+P(10)

= 0.06+0.05=0.11

b. How many students got an A on the quiz

Total students = 1000

Probability of getting A = 0.11 ---- Calculated from (a)

Number of students = 0.11 * 1000

Number of students = 110 students

So,the number of students that got A is 110

c. How many students did not miss a single question

For a student not to miss a single question, then that student scores a total of 10 out of possible 10

P(10) = 0.05

Total Students = 1000

Number of Students = 0.05 * 1000

Number of Students = 50 students

We see that 5

d. Probability that a student pass the quiz

To pass, a student needed to get at least 6 questions right.

So we want P(X>=6);

P(X>=) =P(6)+P(7)+P(8)+P(9)+P(10)

=0.08+0.12+0.15+0.06+0.05=0.46

So, the probability of a student passing the quiz is 0.46

e. Number of students that pass the quiz

Total students = 1000

Probability of passing the quiz = 0.46 ----- Calculated from (d)

Number of students = 0.46 * 1000

Number of students = 460 students

So,the number of students that passed the test is 460

f. Number of students that failed the quiz

Total students = 1000

Total students that passed = 460 ----- Calculated from (e)

Number of students that failed = 1000 - 460

Number of students that failed = 540

So,the number of students that failed is 540

g. Probability that a student got at least one question right

This means that we want to solve for P(X>=1)

Using the complement rule,

P(X>=1) = 1 - P(X<1)

P(X>=1) = 1 - P(X=0)

P(X>=1) = 1 - 0.04

P(X>=1) = 0.96

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Explanation:

JavaPadGUI.java

package javapad.gui;

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import java.awt.event.ActionListener;

import java.awt.event.WindowAdapter;

import java.awt.event.WindowEvent;

import java.io.File;

import java.io.FileNotFoundException;

import java.io.PrintWriter;

import java.util.Scanner;

import javax.swing.JButton;

import javax.swing.JFrame;

import javax.swing.JLabel;

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public class JavaPadGUI extends JFrame implements ActionListener{

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  private static final String FILENAME = "hardcode.txt";

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  private static final String QUIT_MSG = "Quitting, Save?";

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      //set command names for the buttons, these will be when button is clicked

      butNew.setActionCommand(NEW);

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  {

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  }

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  {

      try {

          Scanner s = new Scanner(new File(FILENAME));

          String str = "";

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              str += s.nextLine();

          txtContent.setText(str);

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package javapad;

import javapad.gui.JavaPadGUI;

public class RunJavaPad {

  public static void main(String[] args) {

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