To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

$\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}$

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

$\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}$

4 0

1 year ago

4x^2+4x+1=9 solutions

Artyom0805 [142]

Answer:

4(x-2)(x+1)=0

Step-by-step explanation:

5 0

3 years ago

F(x)=2x+1/x-1 then f^-1(1)

olasank [31]

Answer:

f⁻¹(x) = (x + 1) / (x - 2)
f⁻¹(1 ) = - 2

Step-by-step explanation:

Given function:

f(x) = (2x + 1) / (x - 1)

Find its inverse, substitute x with y and f(x) with x, solve for y:

x = (2y + 1) / (y - 1)
x(y - 1) = 2y + 1
xy - x = 2y + 1
xy - 2y = x + 1
y(x - 2) = x + 1
y = (x + 1) / (x - 2)

Substitute y with f⁻¹(x):

f⁻¹(x) = (x + 1) / (x - 2)

Find f⁻¹(1 ):

f⁻¹(1 ) = ( 1 + 1) / (1 - 2) = 2 / - 1 = - 2

6 0

2 years ago