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Elden [556K]
3 years ago
14

Lucy is a dress maker. She sews 4/7 of a dress in 3/4 hour. Lucy sees at a constant rate. At this rate, how many dresses does lu

cy see in one hour? (Include fractions of dresses if applicable.)
Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

Lucy sews \frac{16}{21} dresses in 1 hour.

Step-by-step explanation:

Given:

Lucy sews \frac{4}{7} of a dress in \frac{3}{4} hour.

She sews at constant rate.

We need to find the number of dresses she makes in 1 hour.

In \frac{3}{4} hour = \frac{4}{7} dress

So in 1 hour = Number of dresses in 1 hour

By using Unitary method we get;

Number of dresses in 1 hour= \frac{\frac{4}{7}}{\frac{3}{4}} = \frac{4}{7}\times \frac{4}{3}= \frac{16}{21}

Hence Lucy sews \frac{16}{21} dresses in 1 hour.

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what do the following two equations represent? please help 4x+2y= 10 4x-2y= -10 a) the same line b) distance parallel lines c) p
Lady bird [3.3K]

Answer:

D

Step-by-step explanation:

The equations are

● 4x + 2y = 10 (1)

● 4x - 2y = -10 (2)

● 4x + 2y = 10

Add - 4x to both sides

● 4x + 2y -4x = 10 -4x

● 2y = 10 -4x

Divide both sides by 2

● 2y/2 = (10 - 4x)/2

● y = 5 - 2x

● y = -2x + 5 (1)

● 4x - 2y = -10

Add -4x to both sides

● 4x -2y -4x = -10 - 4x

● -2y = -10 - 4x

Divide both sides by -2

● -2y/-2 = (-10 -4x)/-2

● y = 10 + 2x

● y = 2x + 5 (2)

So the equation are

● y = 2x + 5

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Graph them

The lines intersect at (0,5) but aren't perpendicular

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8 0
3 years ago
Consider an urn containing 8 white balls, 7 red balls and 5 black balls.
weqwewe [10]

Answer + Step-by-step explanation:

1) The probability of getting 2 white balls is equal to:

=\frac{8}{20} \times \frac{7}{19}\\\\= 0.147368421053

2) the probability of getting 2 white balls is equal to:

=C^{2}_{5}\times (\frac{8}{20} \times \frac{7}{19}) \times (\frac{12}{18} \times \frac{11}{17} \times \frac{10}{16})\\=0.397316821465

3) The probability of getting at least 72 white balls is:

=C^{72}_{150}\times \left( \frac{8}{20} \right)^{72}  \times \left( \frac{7}{20} \right)^{78}  +C^{73}_{150}\times \left( \frac{8}{20} \right)^{73}  \times \left( \frac{7}{20} \right)^{77}  + \cdots +C^{149}_{150}\times \left( \frac{8}{20} \right)^{149}  \times \left( \frac{7}{20} \right)^{1}  +\left( \frac{8}{20} \right)^{150}

=\sum^{150}_{k=72} [C^{k}_{150}\times  \left( \frac{8}{15} \right)^{k}  \times \left( \frac{7}{15} \right)^{150-k}]

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1 year ago
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Y = 3x + 5, x = -4 / So, what would the y equal ?
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Answer:y=4x+1

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