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LenKa [72]
3 years ago
14

Explain why the column of a fractional distillation apparatus should be aligned as near to the vertical as possible

Chemistry
1 answer:
____ [38]3 years ago
7 0
<span><span>The column of a fractional distillation apparatus should be aligned vertical to get better separation because the column is essentially longer. It will prevent channeling in the column. </span>Therefore column efficiency will be higher if it is as vertical as possible instead of tilted.<span> Distillation is a process used to separate a mixture of two (or more) components. In a typical </span>fractional distillation, a liquid mixture is heated in the distilling flask and the process begins.</span>
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What determines density?
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Answer:

D = m/v.

Explanation:

The density of a substance is the relationship between the mass of the substance and how much space it takes up (volume). The mass of atoms, their size, and how they are arranged determine the density of a substance. Density equals the mass of the substance divided by its volume;

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If the edge length of the unit cell is 705.2 pm, what is the density of KI in g/cm3.
Kipish [7]

The density  is 3.144 g / cm^3.

<u>Explanation</u>:

If effective number of atom in NaCl type structure, z = 4

a = 705.2 pm ⇒ In centimeter = 705.2 \times 10^-10

Na = 6.023 \times 10^23

density = (molecular weight) (z) / (Na) (a^3)

where molecular weight of KI is 166 g,

           Z represents the atomic number

density = (molecular weight) (z) / (Na) (a^3)              

             = (166 \times 4) / (6.023 \times 10^23) \times (705.2 \times 10^-10)

density = 3.144 g / cm^3.

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2 years ago
The ph of a solution prepared by mixing 45.0 ml of 0.183 m koh and 35.0 ml of 0.145 m hcl is ________.
Naddika [18.5K]

Answer:

12.6.

Explanation:

  • We should calculate the no. of millimoles of KOH and HCl:

no. of millimoles of KOH = (MV)KOH = (0.183 M)(45.0 mL) = 8.235 mmol.

no. of millimoles of HCl = (MV)HCl = (0.145 M)(35.0 mL) = 5.075 mmol.

  • It is clear that the no. of millimoles of KOH is higher than that of HCl:

So,

[OH⁻] = [(no. of millimoles of KOH) - (no. of millimoles of HCl)] / (V total) = (8.235 mmol - 5.075 mmol) / (80.0 mL) = 0.395 M.

∵ pOH = -log[OH⁻]

∴ pOH = -log(0.395 M) = 1.4.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.4 = 12.6.

4 0
3 years ago
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