

= 2 × 23 + 2 × 52 + 2 × 16
= 182 grams
1 mole of
weighs = 182 g
8 moles weigh = 8× 182
=
or

A solution is prepared by adding 1.43 mol of potassium chloride (kcl) to 889 g of water. The concentration of kcl is 1.61 molal.
mol of Kcl (potassium chloride)= 1.43
water = 889 g
the formula for calculating molality is:
molality = moles of solute/kilograms of solvent
1kg = 1000g so, 889g = 0.889kg
m = 1.43/0.889 = 1.61 molal
Answer:
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Explanation: