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3 years ago

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How many moles of malachite should be formed when 1.5 moles of copper sulphate reacts with an excess of sodium carbonate?

1 answer:

Katen [24]3 years ago

5 0

2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g

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3 years ago

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4 years ago

Read 2 more answers

Hydrogen chloride gas and oxygen react to form water vapor and chlorine gas. What volume of water would be produced by this reac

AlladinOne [14]

Answer: 3.4 L

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given Volume}}{\text {Molar Volume}}=\frac{6.5L}{22.4L}=0.29moles$

The balanced chemical equation for reaction of Hydrogen chloride gas with oxygen to form water vapor and chlorine gas.

$4HCl(g)+O_2(g)\rightarrow 2H_2O(g)+2Cl_2(g)$

According to stoichiometry :

4 moles of $HCl$ produce = 2 moles of $H_2O$

Thus 0.29 moles of $HCl$ will produce = $\frac{2}{4}\times 0.29=0.15moles$ of $H_2O$

Volume of $H_2O=moles\times {\text {Molar Volume}}=0.15moles\times 22.4L/mol=3.4L$

Thus 3.4 L of of water would be produced by this reaction if 6.5 L of hydrogen chloride were consumed

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3 years ago