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frez [133]
3 years ago
10

How many moles of malachite should be formed when 1.5 moles of copper sulphate reacts with an excess of sodium carbonate?

Chemistry
1 answer:
Katen [24]3 years ago
5 0
2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g 
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3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
What is The Magnus Effect/Force? Explain.
cluponka [151]

Answer:

dk

Explanation:

6 0
2 years ago
What is the complete ionic equation for NaOHaq plus HCIaq equals H2OI plus NaCIaq?
OverLord2011 [107]

Answer:

Ionic equation:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq)   →  H₂O(l) + Na⁺(aq) + Cl⁻ (aq)

Explanation:

Chemical equation:

NaOH(aq) + HCl(aq)   →  H₂O(l) + NaCl (aq)

Balanced chemical equation:

NaOH(aq) + HCl(aq)   →  H₂O(l) + NaCl (aq)

Ionic equation:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq)   →  H₂O(l) + Na⁺(aq) + Cl⁻ (aq)

Net ionic equation:

OH⁻(aq) + H⁺(aq)    →  H₂O(l)

The  Cl⁻(aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

3 0
2 years ago
Where are electrons found in the atom?
icang [17]
B




Electrons are found in shells or orbitals that surround the nucleus of an atom
4 0
2 years ago
Read 2 more answers
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