Liquid :) it goes directly from a solid to a gas. Have a nice day!
<span>I would say only if one of your data points is the origin. But your experiment could have started with a non-zero velocity, for instance, which would rule out the origin as one of your data points. Even so, a "best fit" is not meant to be perfect, it is only meant to be the best that you can do with your particular data set.</span>
Yes, Bobby is correct
Explanation:
Anomalously high boiling point of water is as a result of the intermolecular forces between the molecules of water.
The intermolecular forces found in water are the very strong hydrogen bonds. The bulk of the physical properties of matter are due to the intermolecular forces that they possess.
- Hydrogen bonds are stronger than van der waals forces and they are more effective in binding molecules together into larger units.
- Substances whose molecules join via hydrogen bonds have higher boiling points i.e lower volatility than those with van der waals forces.
- Hydrogen bond is actually an electrostatic attraction between hydrogen atom of none molecule and the electronegative atom(O or N or F) of a neighboring molecule.
Learn more:
Hydrogen bonds brainly.com/question/10602513
#learnwithBrainly
Explanation:
P1V1 = nRT1
P2V2 = nRT2
Divide one by the other:
P1V1/P2V2 = nRT1/nRT2
From which:
P1V1/P2V2 = T1/T2
(Or P1V1 = P2V2 under isothermal conditions)
Inverting and isolating T2 (final temp)
(P2V2/P1V1)T1 = T2 (Temp in K).
Now P1/P2 = 1
V1/V2 = 1/2
T1 = 273 K, the initial temp.
Therefore, inserting these values into above:
2 x 273 K = T2 = 546 K, or 273 C.
Thus, increasing the temperature to 273 C from 0C doubles its volume, assuming ideal gas behaviour. This result could have been inferred from the fact that the the volume vs temperature line above the boiling temperature of the gas would theoretically have passed through the origin (0 K) which means that a doubling of temperature at any temperature above the bp of the gas, doubles the volume.
From the ideal gas equation:
V = nRT/P or at constant pressure:
V = kT where the constant k = nR/P. Therefore, theoretically, at 0 K the volume is zero. Of course, in practice that would not happen since a very small percentage of the volume would be taken up by the solidified gas.
The misture can be separated by filtration.
