Which pair of elements is both malleable and able to conduct heat?

The gas-phase reaction follows an elementary rate law and is to be carried out first in a PFR and then in a separate experiment

astraxan [27]

Answer:

The activation energy is $=8.1\,kcal\,mol^{-1}$

Explanation:

The gas phase reaction is as follows.

$A \rightarrow B+C$

The rate law of the reaction is as follows.

$-r_{A}=kC_{A}$

The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" = $10dm^{3}$

Temperature "T" = 300 K

Volumetric flow rate of the reaction $v_{o}=5dm^{3}s$

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

$V= \frac{v_{0}}{k}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]$

Rearrange the formula is as follows.

$k= \frac{v_{0}}{V}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]............(1)$

The feed has Pure A, mole fraction of A in feed $y_{A_{o}}$ is 1.

$\epsilon =y_{A_{o}}\delta$

$\delta$ = change in total number of moles per mole of A reacte.

$=1(2-1)=1$

Substitute the all given values in equation (1)

$k=\frac{5m^{3}/s}{10dm^{3}}[(1+1)ln \frac{1}{1-0.8}-1 \times 0.8] = 1.2s^{-1}$

Therefore, the rate constant in case of the plug flow reacor at 300K is $1.2s^{-1}$

The rate constant in case of the CSTR can be calculated by using the formula.

$\frac{V}{v_{0}}= \frac{X(1+\epsilon X)}{k(1-X)}.............(2)$

The feed has 50% A and 50% inerts.

Hence, the mole fraction of A in feed $y_{A_{o}}$ is 0.5

$\epsilon =y_{A_{o}}\delta$

$\delta$ = change in total number of moles per mole of A reacted.

$=0.5(2-1)=0.5$

Substitute the all values in formula (2)

$\frac{10dm^{3}}{5dm^{3}}=\frac{0.8(1+0.5(0.8))}{k(1-0.8)}=2.8s^{-1}$

Therefore, the rate constant in case of CSTR comes out to be $2.8s^{-1}$

The activation energy of the reaction can be calculated by using formula

$k(T_{2})=k(T_{1})exp[\frac{E}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})]$

In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

$E= R \times(\frac{T_{1}T_{2}}{T_{1}-T_{2}})ln\frac{k(T_{2})}{k(T_{1})}$

Substitute the all values.

$=1.987cal/molK(\frac{300K \times320K}{320K \times300K})ln \frac{2.8}{1.2}=8.081 \times10^{3}cal\,mol^{-1}$

$=8.1\,kcal\,mol^{-1}$

Therefore, the activation energy is $=8.1\,kcal\,mol^{-1}$

8 0

3 years ago

How do submarine volcanoes affect autotrophic bacteria?

Anarel [89]

Answer:A large number of autotrophic bacteria—bacteria that produce their own food—live near hydrothermal vents and submarine volcanoes.

These bacteria are considered chemosynthetic, meaning they produce food from chemical reactions usually involving carbon dioxide, oxygen, or hydrogen

5 0

2 years ago

What is said to have happened to the electrons in an atom in its ground state absorbs a quantum of energy from light

Rus_ich [418]

Answer:

The electron from the ground state to occupy a next energy level. In this case,we say that the electron is excited

3 0

3 years ago

What conversion factor is present in almost all stoichiometry calculations?

luda_lava [24]

<h3><u>Answer;</u></h3>

Molar mass

<h3><u>Explanation</u>;</h3>

Stoichiometry involves the study of quantitative relationships between the amounts of reactants used and products formed by a chemical reaction.
A conversion factor is a ratio of coefficients found in a balanced reaction, which can be used to inter-convert the amount of products and reactants.
Molar ratios, or conversion factors, identify the number of moles of each reactant needed to form a certain number of moles of each product.

8 0

3 years ago

WILL GIVE POINTS/MARK BRAINLIST! Question 6: Types of Molecular Shapes (3 points) Identify the following molecular shapes. (0.5

Vanyuwa [196]

Answer:

A. tetrahedral

B. angular or bent

C. angular

D. trigonal planar

E. linear

F. linear

Explanation:

8 0

2 years ago