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3 years ago

In the decimal number .675, the 7 holds what place value

Mathematics

2 answers:

aliya0001 [1]3 years ago

8 0

7 is representing the hundredth's place.

Sergio039 [100]3 years ago

7 0

<span>To see 7's rank we can count the number of digits after ".". 7 is the second digit and given that the first digit represents the decimals, 7 will represent the hundreths. </span>

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Factor over the complex numbers: 36x2 + 9.

ludmilkaskok [199]

$36x^2+9=(6x)^2-(-9)=(6x)^2-(-3^2)\\\\=(6x)^2-(3i)^2=(6x-3i)(6x+3i)\\\\\text{Used:}\\a^2-b^2=(a-b)(a+b)\\\\i^2=-1$

4 0

3 years ago

Hey guys i just joined how do i do this

Sergeeva-Olga [200]

Answer: you can ask questions your struggling with and people like me will help you answer them. You can also help other people answer their questions and get points for it

Step-by-step explanation:

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3 years ago

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Determine the graph of the polar equation r=4/(1-1/2cosx(theta))

crimeas [40]

Answer:

see below

Step-by-step explanation:

We assume you want the graph of ...

$r=\dfrac{4}{1-\frac{1}{2}\cos{(\theta)}}$

A graphing calculator or spreadsheet is useful for this.

You know cos(θ) = cos(-θ), so the graph is symmetrical about the x-axis. You can evaluate the function at a few points to find the general outline.

r at 0° = 8

r at 30° ≈ 7.05

r at 45° ≈ 6.19

r at 60° ≈ 5.33

r at 90° = 4

r at 120° = 3.2

r at 135° ≈ 2.96

r at 150° ≈ 2.79

r at 180° ≈ 2.67

6 0

3 years ago

Given the vectors u= <2, 1> and v= <5, 4>, determine the components of a vector represented by 2u - 3v

kati45 [8]

Answer:

C.) <-11, -10>

Step-by-step explanation:

Let's define how to work with vectors.

For two vectors:

V = <a, b>

W = <c, d>

The product of a scalar k and a vector is given by:

k*V = k*<a, b> = <k*a, k*b>

And the sum (or difference) of two vectors is given by:

V ± W = <a, b> ± <c, d> = <a ± c, b ± d>

Now that we know this, we can solve the problem.

Here we have the vectors:

u = <2, 1>

v = <5, 4>

then:

2u - 3*v = 2*<2, 1> - 3*<5, 4>

= <2*2, 2*1> - <3*5, 3*4>

= <4, 2> - <15, 12>

= <4 - 15, 2 - 12>

= < -11, -10>

Then the correct option is C.

5 0

3 years ago

For each system of equations, drag the true statement about its solution set to the box under the system?

natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

coefficients of x and y are the same and the numerical terms

are the same

- The system of equation has one solution if at least one of the

coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0

3 years ago