The mass of chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.
The mass of chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.
The given parameters;
- <em>mass of the sodium chloride, = 14.5 g</em>
- <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>
<em />
In the reaction above, we can deduce the following;
molecular mass of 2Nacl = 2(58.44) = 116.88 g
molecular mass of 2NaF = 2(42) = 84 g
molecular mass of Cl2 = 71 g
The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 84 g of NaF
14.5 g of NaCl ------------------- ?
The mass of chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 71 g of Cl2
14.5 g of NaCl ------------------- ?
Learn more here:brainly.com/question/8470145
Answer:
<em>Three (3) of the molecules are polar: </em>
<em> </em>
<em> </em>
<em>.</em>
Explanation:
Polar substances have their elements held together by a covalent bond that contain partially positive and negative charges, which results in a difference in the charges' electronegativity difference (usually ranging between 0.4 and 0.7).
- PCl5 is <u>non-polar</u> with a symmetric geometry
- CoS is <u>polar</u>
- XeO3 is <u>polar</u>, with a trigonal pyramidal molecular geometric
- SeBr2 is <u>polar</u> as the difference their electronegativity is about ).5
Hey there !
Given the reaction:
N2 + 3 H2 = 2 NH3
At constant pressure and temperature ,volume is proporcional to moles:
Theoretical moles of N2 and H2 => 1:3
Theoretical volume of N2 and H2 => 1:3
Experimental volume of N2 and H2 => 3.0 L : 4.0 L
0.75 : 1 = 2.25 : 3
Since N2 is in excess reactant , H2 is the limiting reactant
Therefore:
volume of NH3 is 2/3 * Volume of H2
= 2/3 * 4.0 = 2.66 L
Hope that helps!
In order to answer this, you need to find the empirical data for the standard entropies. Please refer to this link: http://www.mrbigler.com/misc/energy-of-formation.PDF
For NO₂ gas, the entropy is 240 J/mol-K. For N₂O₄ gas, the entropy is 304.2 J/mol-K. Therefore, <em>the statement is false.</em>
