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3 years ago

What is the ground state configuration of Co3+?

1 answer:

4 0

Cobalt has an atomic number of 27, which means that its atoms have 27 protons in their nuclei. In a neutral cobalt atom, there is also 27 electrons. The ground stateelectron configuration of cobalt is [Ar]3d74s2 .

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5. A study of the system, 4 NH3(g) + 7 O2(g) 2 N2O4(g) + 6 H2O(g), was carried out. A system was prepared with [NH3] = [O2] = 3.

emmasim [6.3K]

Answer: The value of the equilibrium constant, Kc, for the reaction is 0.013

Explanation:

Initial concentration of $NH_3$ = 3.60 M

Initial concentration of $O_2$ = 3.60 M

The given balanced equilibrium reaction is,

$4NH_3(g)+7O_2(g)\rightleftharpoons 2N_2O_4(g)+6H_2O(g)$

Initial conc. 3.60 M 3.60 M 0 M 0 M

At eqm. conc. (3.60-4x) M (3.60-7x) M (2x) M (6x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[N_2O_4]^2\times [H_2O]^6}{[NH_3]^4\times[Cl_2]}$

$[N_2O_4]=0.60M$

2x = 0.60 M

x= 0.30 M

Now put all the given values in this expression, we get :

$K_c=\frac{(2\times 0.30)^2\times (6\times 0.30)^6}{(3.60-3\times 0.30)^4\times (3.60-7\times 0.30)^7}$

$K_c=0.013$

6 0

3 years ago

152 dm^3 of gas has a pressure of 98.6 kpa. at what pressure will the volume be quartered

djverab [1.8K]

Answer:

P₂ = 394.4 KPa

Explanation:

Given data:

Volume of gas = 152 dm³

Pressure of gas = 98.6 KPa

Final pressure = ?

Final volume = quartered = 1/4×152 = 38 dm³

Solution:

P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

P₂ = 98.6 KPa . 152 dm³ / 38 dm³

P₂ = 14987.2 KPa. dm³ / 38 dm³

P₂ = 394.4 KPa

6 0

3 years ago

Which statement describes a benefit of using fission reactions?

AysviL [449]

gamma radiation is produced Explanation:nun

8 0

3 years ago

Read 2 more answers

Which of the following statements is true?

vaieri [72.5K]

I think D?? I apologize if not-check in other answers to be sure ^^

7 0

3 years ago

Read 2 more answers

What is the predicted change in the boiling point of water when 1.50 g of

dezoksy [38]

Answer:

0.00735°C

Explanation:

By seeing the question, we can see the elevation in boiling point with addition of BaCl₂ in water

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$\textsf {While} \: \sf {\Delta T_b} \: \textsf{expression is used} \\ \textsf {for elevation of boiling point}$

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The elevation in boiling point is a phenomenon in which there is increase in boiling point in solution, when the particular type of solute is added to pure solvent.

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$\sf \large \underline{The \: formula \: to \: be \: used \: in \: this \: question \: is} \\ \boxed{T_b = i \times K_b \times m}$

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Where 'i' is van't hoff factor which represents the ratio of observed osmotic pressure and the value to be expected.

and 'i' is 3 (as given in the question)

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'Kb' is molal boiling point constant. And it's value is 0.51°C/mol(given in question)

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'm' represent the molality of solution. Molatity is no. of moles of solution present in 1kg of solution.

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To find molality, we have to divide no. of moles of solute by weight of solution

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While first we need to no. of moles

$\sf \implies no. \: of \: moles = \frac{weight \: of \: solute}{molar \: mass \: of \: solute} \\ \\ \implies \sf no. \: of \: moles = \frac{1.5}{208.23} \\ \\ \sf \implies no. \: of \: moles = 0.0072$

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Now, we will find molality

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$\sf \hookrightarrow molality = \frac{no.\: of \: moles}{weight \: of \: solution} \\ \\ \sf \hookrightarrow molality = \frac{0.072}{1.5} \\ \\ \sf \hookrightarrow molality = 0.048 \: mol {kg}^{ - 1}$

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$\textsf{ \large{ \underline{Now substituting the required values}}}$

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$\sf \longmapsto \Delta T_b = 3 \times 0.51 \times 0.0048 \\ \\ \\ \boxed{ \tt{ \longmapsto \Delta T_b =0.00735{ \degree}C}}$

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Henceforth, the change in boiling point is 0.00735°C.

7 0

2 years ago