Question

How many grams of sucrose are in 1.80 of a 0.718 sucrose solution

Answer 1

Answer:

445 g

Explanation:

Data Given:

Volume of sucrose solution = 1.8 L

Molarity of sucrose solution = 0.718 M

mass of solute = ?

Solution:

First we will find mole of solute in a Molar Solution of sucrose

Formula used

                 Molarity = No. of moles of solute / of solution in L

where

solute is sucrose

Put Values in above equation

                0.718 M = No. of moles of sucrose / 1.8 L

Rearrange the equation as we have to find moles of sucrose

                No. of moles of sucrose = 0.718 x 1.8

               No. of moles of sucrose = 1.3 mole

Now,

we have to find mass of sucrose

For this formula will use

                     mass in grams = no. of moles x Molar mass . . . . . .(1)

Formula of Sucrose = C₁₂H₂₂O₁₁

Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 12(12) +22(1) +11(16)

Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 144 +22 + 176

Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 342 g/mol

put values in equation 1

                    mass in grams = 1.3 mol x 342 g/mol

                    mass in grams = 444.6 g

Round the figure. So,

mass of C₁₂H₂₂O₁₁ (Sucrose) = 445 g