2 years ago

The lift does 3000 J of work in 5 seconds. What is the power of the lift?

Physics

1 answer:

diamong [38]2 years ago

8 0

Answer:

600

Explanation:

p=Work/time

3000/5=600 is power

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3. 3.0*1015 electrons are removed from one side of a parallel plate capacitor and travel to the other side of the capacitor. You

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True

$Q = 480 \mu C$

Explanation:

As we know that total charge is always quantized and in the terms of multiples of charge of single electron

so we have

Q = Ne

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$N = 3.0 \times 10^{15}$

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so we have

$Q = (3.0 \times 10^{15})(1.6 \times 10^{-19} C)$

$Q = 480 \mu C$

Since this charge is in multiple of micro coulomb units so yes it is possible to measure it

and the magnitude of this charge is given as

$Q = 480\mu C$

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