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In-s [12.5K]
3 years ago
8

The lift does 3000 J of work in 5 seconds. What is the power of the lift?

Physics
1 answer:
diamong [38]3 years ago
8 0

Answer:

600

Explanation:

p=Work/time

3000/5=600 is power

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Which of the materials would be able to scratch Quartz
Lelechka [254]
<span>anything harder than mohs scale 7 so eg Topaz, Corundum and diamond representing mohs scale 8 9 and 10 respectively.</span>
7 0
3 years ago
You calculate the density of a block of aluminum to be 2.68 g/cm3. You look up the density of a block of aluminum at room temper
Hunter-Best [27]

Answer:

Systematic errors.

Explanation:

The density of the aluminium was calculated by a human and this is not natural but can be due to errors in the calibration of the scale for measuring the weight or taking readings from the measuring cylinder.

Random errors are natural errors. Random errors in experimental measurements are caused by unknown and unpredictable changes in the experiment. Systematic errors are due to imprecision or problems with instruments.

3 0
3 years ago
A block of mass m is attached to a rope wound around the outer rim of a disk of radius R and moment of inertia I, which is free
Hoochie [10]

Answer:

Explanation:

I is the moment of inertia of the pulley, α is the angular acceleration of the pulley and T is the tension in the rope. Let a is the linear acceleration.

The relation between the linear acceleration and the angular acceleration is

a = R α   .... (1)

According to the diagram,

T x R = I x α

T x R = I x a / R      from equation (1)

T = I x a / R²      .... (2)

mg - T = ma    .... (3)

Substitute the value of T from equation (2) in equation (3)

mg - \frac{Ia}{R^{2}}=ma

a=\frac{mg}{m+\frac{I}{R^{2}}}

T is the acceleration in the system

Substitute the value of a in equation (2)

T = \frac{I}{R^{2}}\times \frac{mg}{m+\frac{I}{R^{2}}}

T=\frac{I\times mg}{I+mR^{2}}

This is the tension in the string.

4 0
3 years ago
if you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1234 kg, how strong is the for
bagirrra123 [75]

Gravitational force between two masses is given by formula

F = \frac{Gm_1m_2}{r^2}

here we know that

m_1 = 55 kg

m_2 = 1234 kg

r = 3 m

G = 6.67 \times 10^{-11} Nm^2/kg^2

now from the above equation we will have

F = \frac{(6.67 \times 10^{-11})(55)(1234)}{3^2}

F = 5.03 \times 10^{-7}N

so above is the gravitational force between car and the person

5 0
2 years ago
In general, an organism will be more likely to develop phobias of __________.
BARSIC [14]

Answer:

a) dangers faced during natural circumstances

7 0
2 years ago
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