Answer:
The time rate of change of flux is

Explanation:
Given :
Current
A
Area of plate

Plate separation
m
(A)
First find the capacitance of capacitor,

Where 

F
But 
Where 


Now differentiate above equation wrt. time,



Therefore, the time rate of change of flux is

Answer:

Explanation:
We first identify the elements of this simple harmonic motion:
The amplitude A is 8.8cm, because it's the maximum distance the mass can go away from the equilibrium point. In meters, it is equivalent to 0.088m.
The angular frequency ω can be calculated with the formula:

Where k is the spring constant and m is the mass of the particle.
Now, since the spring starts stretched at its maximum, the appropriate function to use is the positive cosine in the equation of simple harmonic motion:

Finally, the equation of the motion of the system is:
or

The answer would be, "1/560 seconds".
Answer:
Explanation:
It is easier to see clothes with pointed needle than a blunt one because pressure exerted is more in a pointed needle as it occupies less space compared to blunt needle, A blunt has more surface area so the pressure exerted will less as compared to a pointed needle.
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