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erik [133]
2 years ago
15

In general, an organism will be more likely to develop phobias of __________.

Physics
1 answer:
BARSIC [14]2 years ago
7 0

Answer:

a) dangers faced during natural circumstances

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For your answer to this problem, just type in the numerical magnitude of the momentum - no units.
stepan [7]

Answer:

120 kg•m/s.

Explanation:

From the question given above, the following data were obtained:

Case 1

Mass of object = M

Velocity of object = V

Momentum = 15 kg•m/s

Case 2

Mass of object = 2M

Velocity of object = 4V

Momentum = ?

Momentum is defined as follow:

Momentum = mass × velocity

The momentum of object in case 2 can be obtained as follow:

From case 1

Momentum = mass × velocity

15 = M × V

15 = MV ....... (1)

From case 2:

Momentum = mass × velocity

Momentum = 2M × 4V

Momentum = 8MV ....... (2)

Finally , substitute the value of MV in equation 1 into equation 2.

Momentum = 8MV

MV = 15

Momentum = 8 × 15

Momentum = 120 kg•m/s

Therefore, an object with a mass of 2M and 4V would have a momentum of 120 kg•m/s

3 0
3 years ago
Rupert (66 kg) is now in a full-pipe of radius 25 m, calculate the minimum speed at which Rupert can skate to ensure he will not
V125BC [204]

at the top most point if Rupert will not fall then normal force at the top point is almost zero for minimum speed

so here we can say

F_n + mg = m\frac{v^2}{R}

now if

F_n = 0

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = \sqrt{25 \times 9.8}

v = 15.65 m/s

so above will be the minimum speed

4 0
3 years ago
What is the main purpose of trying to quickly cool heated food?
Ronch [10]
You can eat the food
8 0
2 years ago
Read 2 more answers
Which statement about bout waves is correct?
Eva8 [605]

Answer:

In light waves, the electromagnetic fields oscillate perpendicular to the direction of propagation. Hence, sound waves are longitudinal waves whereas light waves are transverse waves.

6 0
2 years ago
3. Suppose you take a pendulum with length L and mass m having a period T to a
natta225 [31]

(C)

Explanation:

t = 2\pi \sqrt{ \frac{l}{g} }

If g is only 1/6 on another planet, then

t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } =  2\pi \sqrt{ \frac{6l}{g} }

=  \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4  \times t(on \: earth)

6 0
2 years ago
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