Ask question

Ask question

All categories

3 years ago

5

What is a rule that assigns each value of the independent variable to exactly one value of the dependent variable

1 answer:

mr Goodwill [35]3 years ago

8 0

Where is the answers choices

You might be interested in

Kyleigh is making a bowl of punch. The recipe calls for 2 1/4 cups for sherbet. If she uses 1 2/3 of that amount, will she be us

ankoles [38]

Less than the original amount of sherbet

3 0

3 years ago

Find the area of a rectangle with a base of 5 feet and a height of 9 1/2 feet

gayaneshka [121]

The area of the rectangle is 47 1/2

7 0

2 years ago

A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable

Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.3$ .

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066$

$P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014$

$P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002$

$P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024$

$P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002$

$P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0$

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082$

0.0082 = 0.82% probability that he will pass

6 0

2 years ago

Matthew is 3 times as old as jenny. in 7 years, he will be twice as old as she will be then. how old is each now? Explain how to

Nataliya [291]

Let m and j be the current ages of Matthew and Jenny, respectively.

Now, Matthew is 3 times as old as Jenny, so the variables are in the following relation:

$m=3j$

In 7 years, both of them will be 7 years older, i.e. their ages will be m+7 and j+7, and Matthew will be twice as old:

$m+7=2(j+7)$

Now, remembering that m=3j, we can rewrite the second equation as

$3j+7=2j+14 \iff j = 7$

So, Jenny is 7 and Matthew is 21 (he's 3 times older).

In fact, in 7 years, they will be 14 and 28, and Matthew will be twice as old.

7 0

2 years ago

On Wednesday a local hamburgers shop sold a combined total of 568 hamburgers and cheeseburgers. The number of cheeseburgers sold

Sphinxa [80]

Answer:

i think its 142

5 0

3 years ago