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xxTIMURxx [149]
3 years ago
13

Uranium-238 undergoes alpha decay. Therefore, uranium-238 will increase,decrease,stay the same or none of the above

Physics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Decrease

Explanation:

When a U-238 nuclei undergoes alpha decay, the nuclei will decrease substantially.

An alpha particle will cause a decrease in the mass number of the nuclei by 4 and the atomic number by 2.

  The reaction is shown below;

                       ²³⁸₉₂U   →  ²³⁴₉₀Th   +   ⁴₂He

We see that during an alpha decay, the mass number changes from 238 to 234 and that atomic number from 92 to 90.

learn more:

Transmutation brainly.com/question/3433940

#learnwithBrainly

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the diagram below shows a segment of DNA before and after erplication, which of the following could have occured as a result of
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The change or mutation in a segment of DNA after replication may lead to changes in the genotype, the traits of the organism and the proteins (option i, ii and iii).

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A genetic mutation is any change in the nucleotide bases of the genome of an organism that may be associated with modifications in the phenotypic traits or features of the organism if this change alters the expression of a given gene that produces a particular protein.

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2 years ago
a 60-kg skier starts at the top of a 10 meter slope. At the bottom, she is traveling 10 m/s. How much energy does she loose to f
Alex
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4 years ago
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denis-greek [22]
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To find the product of 183.5 and 10², move the decimal point in 183.5
S_A_V [24]

Answer:

Given :

To find the product of 183.5 and 10², move the decimal point in 183.5 _____ places to the right because 10² has _____ zeros.

To Find :

We need to fill the spaces.

Solution :

We know, when number with positive power of 10 is multiplied with another number we need to shift the number to the right hand side by the number of zeroes.

So, To find the product of 183.5 and 10², move the decimal point in 183.5 to right places to the right because 10² has two zeros.

Hence, this is the required solution.

Explanation:

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