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Bogdan [553]
3 years ago
5

Steel Usually forms a

Physics
1 answer:
meriva3 years ago
6 0

Answer:

Permanent magnetism (of the steel)

make me brainliestt :))

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A spring is stretched 5 cm from its equilibrium position. If this stretching requires 30 J of work,
Triss [41]

Answer:

Best answer will get Brainliest!!!

What is the volume scaled down by a factor of 1/10

Measurements:

Top: 7 in, both sides: 12 in, front: 12 in, back: 12 in, bottom: 7 in

Please help!

Explanation:

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2 years ago
What is a therapuetic modality in psychology?
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There are several modalities, or methods, of treatment: individual therapy, group therapy, couples therapy, and family therapy

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2 years ago
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Complete the ray diagram and label incident ray, refracted ray, angle of incidence, and angle of refraction ​
Novay_Z [31]

Answer:

Solution

verified

Verified by Toppr

(a) The labelled diagram is shown.

(b) The refractive index of diamond is 2.42. Refractive index of diamond is the ratio of the speed of light in air to the speed of light in diamond.i.e.,

μ=  

Speedoflightindiamond

Speedoflightinair

​

 

and, the ratio of these velocities is 2.42. i.e., This means that the speed of light in diamond will reduce by a factor of 2.42 as compared to its speed in air. In other words, the speed of light in diamond is  

1/2.42

times the speed of light in vacuum.

Explanation:

a) Draw and label the diagram given :

  (i) Incident ray

  (ii) Refracted ray

  (iii) Emergent ray

  (iv) Angle of reflection

  (v) Angle of deviation

  (v) Angle of emergence

(b) The refractive index of diamond is 2.42. What is the meaning of this statement in relation to speed of light?

4 0
3 years ago
Calculate the work done on a Pressure / Volume (PV) isothermal expansion where 400 Pa and 0.08 volume in m3?
Ainat [17]
PV = 400 x 0.08 = 32 J

Hope this helps
7 0
3 years ago
Who water rocket starts from rest and roses straight up with an acceleration of 5 m/s until it runs out of water 2.5 seconds lat
Kitty [74]

Answer:

23. 4375 m

Explanation:

There are two parts of the rocket's motion

1 ) accelerating  (assume it goes upto  h1 height )

using motion equations upwards

s = ut+\frac{1}{2}*a*t^{2} \\h_1=0+\frac{1}{2}*5*2.5^{2} \\=15.625 m

Lets find the velocity after 2.5 seconds (V1)

V = U +at

V1 = 0 +5*2.5 = 12.5 m/s  

2) motion under gravity (assume it goes upto  h2 height )

now there no acceleration from the rocket. it is now subjected to the gravity

using motion equations upwards (assuming g= 10m/s² downwards)

V²= U² +2as

0 = 12.5²+2*(-10)*h2

h2 = 7.8125 m

maximum height = h1 + h2

                            = 15.625 + 7.8125

                            = 23. 4375 m

3 0
3 years ago
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