If the cross-section of a wire of fixed length is doubled, how does the resistance of that wire change? (this is for studying fo
1 answer:
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Answer:
0.0483m or 48.3 mm
Explanation:
Let g = 10m/s2
At 8m, the pile has a potential energy of
P = mgh = 3000*10*8 = 240000 J
This energy is converted to kinetic energy once the pile drops down to the bottom:
Taking gravity into consideration, the net force acting on the pile once it hits the ground is
Therefore the net deceleration is:
We can find out how far it's driven into the ground with the following equation of motion:
where v = 0 is the final velocity, which is 0 because it stops, is the initial velocity when it hits the ground, a is the deceleration, and s is the distance it travels into the ground
or 48.3 mm
Answer:
Compression in the spring, x = 0.20 m
Explanation:
Given that,
Spring constant of the spring, k = 490 N/m
Mass of the block, m = 5 kg
To find,
Compression in the spring.
Solution,
Since the block is suddenly dropped on the spring gravitational potential energy of block converts into elastic potential energy of spring. Its expression is given by :
Where
x is the compression in the spring
x = 0.20 m
So, the compression in the spring due to block is 0.20 meters.