Answer:
24 atm is the total pressure exerted by the gases
Explanation:
We propose this situation:
In a vessel, we have 4 gases (for example, hydrogen, Xe, methane and chlorine)
Each of the gases has the same pressure:
6 atm → hydrogen
6 atm → xenon
6 atm → methane
6 atm → chlorine
To determine the total pressure, we sum all of them:
Partial pressure H₂ + Partial pressure Xe + Partial pressure CH₄ + Partial pressure Cl₂ = Total P
6 atm + 6 atm + 6 atm + 6 atm = 24atm
First, find moles of gold given the mass of the sample:
(35.9g Au)/(197.0g/mol Au) = 0.182mol Au
Second, multiply moles of Au by Avogrado's number:
(0.182mol)(6.02 x10^23)= 1.10x10^23 atoms Au
Answer:
B. The outer most occupied energy level has an octet of electrons.
D. None of the above.
C. A hydrogen molecule and hydrogen molecule.
PV=nRT
PV= (m/M)RT
PM=(m/v)RT
PM =dRT
d= (PM) ÷(RT)
substitute the the given data to the above equation. d-density, p-pressure, M- molar mass of argon gas, T- temperature. and R is a constant. make sure to substitute its value too.. :)
