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Nookie1986 [14]
3 years ago
8

The complete combustion of acetylene, C2H2(g), produces 1300. kJ of energy per mole of acetylene consumed. How many grams of ace

tylene must be burned to produce enough heat to raise the temperature of 1.00 gal of water by 12.0°C if the process is 88.0% efficient? Assume the density of water is 1.00 g/cm3.
Chemistry
1 answer:
Wittaler [7]3 years ago
4 0
Be r fs d d d d d w. A w a d d
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Please Please Please Please Please Help Me (please answer this question completely and 1 will friend you and help you with your
pav-90 [236]

Answer:

Static electricity is a type of energy that is produced by friction.

Explanation:

Static electricity may be the result when there is an imbalance between the negative charges and the positive charges in the surroundings. They are non contact forces. They pull of push without actually touching the body. The charged particles interact by pulling or pushing the uncharged particles.

These charges are released when they come closer to some uncharged or other charged particles like the electrostatic charges. It is the charge build up in an area.

6 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.87 L was placed in a weighted balloon and dropped into the ocean. As the
Ludmilka [50]

Answer:

Volume of sample after droping into the ocean=0.0234L

Explanation:

As given in the question that gas is idealso we can use ideal gas equation to solve this;

Assuming that temperature is constant;

Lets P_1 and V_1 are the initial gas parameter before dropping into the ocean

and P_2 and V_2 are the final gas parameter after dropping into the ocean

according to boyle 's law pressure is inversly proportional to the volume at constant temperature.

hence,

P_1V_1=P_2V_2

P1=1 atm

V1=1.87L

P2=80atm

V2=?

After putting all values we get;

V2=0.0234L

Volume of sample after droping into the ocean=0.0234L

7 0
3 years ago
For the reaction CO2(g) + H2(g)CO(g) + H20(g)
Studentka2010 [4]

Answer:

The ΔG° is 29 kJ and the reaction is favored towards reactant.

Explanation:

Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,  

ΔG° = ΔH°rxn - TΔS°rxn

= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K

= 41.2 kJ - 12.2 kJ

= 29 kJ

As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.  

5 0
3 years ago
You have a 28.2-g sample of a metal heated to 95.2°c. you drop it in a calorimeter with 100. g of water at 25.1°c. the final tem
Vlad [161]

The heat lost by the metal should be equal to the heat gained by the water. We know that the heat capacity of water is simply 4.186 J / g °C. Therefore:

100 g * 4.186 J / g °C * (31°C – 25.1°C) = 28.2 g * Cp * (95.2°C - 31°C)

<span>Cp = 1.36 J / g °C</span>

4 0
3 years ago
g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu
scZoUnD [109]

Answer:

CuCl_2 is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

\frac{1}{2}\times 0.500 mol=0.250 mol of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give  :

\frac{2}{2}\times 0.500 mol=0.500 mol of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0
3 years ago
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