We first calculate the heat released:
Specific heat = 3.21 kJ/kgK
Heat released = heat absorbed by calorimeter
Heat absorbed = mcΔT
= 1.9 x 3.21 x 4.542
= 27.7 kJ
Now, we calculate the moles of hexane present:
Moles = mass / Mr
moles = 0.58 / (12 x 6 + 14)
= 0.0067
Heat of combustion = 27.7 / 0.0067 kJ/mol
ΔH(combustion) = 4,134.3 kJ / mol
The brother is represented by variable b.
The sister is represented by the variable s.
This means:
b+s=26
Answer:
Metals Good conductors of electricity good conductors of heat
High density
Malleable and ductile
Non-metals
Poor conductors of electricity
Poor conductors of heat
Low density
brittle
CO(g) +2H2--->CH3OH
2.50g H2*1mol/2g=1.25 mol H2
30.0L CO*1mol/22.4L=1.34 mol CO,
according to reaction 1 mol CO needs 2 mol H2,so 1.34 mol CO need 2.68 mol H2, so 1) limiting teactant is H2 (H)
2)1.25 mol CH3OH will be produced, 1.25 mol*32g/mol=40.0 g CH3OH
3) 1.25 mol H2 needs 0.625 g CO
1.34-0.625=0.715 g CO leftover
