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iren2701 [21]
3 years ago
11

PLEASE HELP!!!!

Physics
1 answer:
mylen [45]3 years ago
5 0
Frequency = (wave speed) / (wavelength)

Frequency = (24 m/s)  /  (2 m)

Frequency = 12 per second . 

Where is that space to put the answer into ?
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The disk rotates about a fixed axis through point O with a clockwise angular velocity ω0 = 16 rad/s and a counterclockwise angul
Lapatulllka [165]

Answer:

V = 4.48m/s a = 1.57m/s²

Explanation:

ω₀ = 16rad/s

α₀ = 5.6rad/s²

r = 280mm = 0.28m

a = ?

v = ?

Angular velocity (ω₀) = velocity of acceleration / length of path

ω₀ = v / r

V = ω₀ * r

V = 16 * 0.28

V = 4.48m/s

Acceleration = ?

Angular acceleration α₀ = angular velocity (ω) / time take (t)

α₀ = ω / t .... equation i

But acceleration (a) = velocity (v) / time (t)

a = v / t

t = v / a

Put t = v / a into equation i

α₀ = ω / (v / a)

α₀ = ω * a / v

α * v = ω * a

a = (α * v) / ω

a = (5.6 * 4.48) / 16

a = 1.568m/s²

a = 1.57m/s²

3 0
3 years ago
How far something moves in a specific amount of time
Svetlanka [38]
Distance is how far something moves in a specific amount of time. 
5 0
3 years ago
Read 2 more answers
Please Please Please Can Help Me On This Question!!!!! I Give Thanks!!!! Please Do 1-4!!!! Please Please Help Nobody Is Helping
DENIUS [597]
Not sure if this is what you’re looking for. Let me know if I can clarify anything.

6 0
3 years ago
Which of the following processes could NOT be used to separate dissolved particles from the liquid in a solution? *
DIA [1.3K]

Answer:

Vaporation

Explanation:

In the vaporization or boiling, the passage of particles from the liquid state to the gaseous state occurs completely

5 0
4 years ago
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(I) A novice skier, starting from rest, slides down an icy frictionless 8.0° incline whose vertical height is 105 m. How fast is
Vlad1618 [11]

Answer:

v = 45.37 m/s

Explanation:

Given,

angle of inclination = 8.0°

Vertical height, H  = 105 m

Initial K.E. = 0 J

Initial P.E. = m g H

Final PE = 0 J

Final KE = \dfrac{1}{2}mv^2

Using Conservation of energy

KE_i + PE_i + KE_f + PE_f

0 + m g H = \dfrac{1}{2}mv^2 + 0

v = \sqrt{2gH}

v = \sqrt{2\times 9.8 \times 105}

v = 45.37 m/s

Hence, speed of the skier at the bottom is equal to v = 45.37 m/s

3 0
3 years ago
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