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3 years ago

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Which of the following is a major reason for increased female participation in collegiate athletics?1. Title IX legislation2. mo

re college teams available3. high school teams more available now than in the past4. more female coaches

1 answer:

choli [55]3 years ago

8 0

Answer:

1. Title IX legislation

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If a hydrogen atom has its electron in the n= 4 state, how much energy in eV is needed to ionize it?

ololo11 [35]

Answer:

Explanation:

Energy of electron in n = 4 state

= - 13.6/4² =- 0.85 eV

So energy needed to extract it from atom = .85 eV.

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3 years ago

What will happen to the pitch of a sound as that sound’s source approaches an observer? Explain why this happens, based on what

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The pitch of a sound is decreased, when a sound source approaches the observer.

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Pitch is nothing but it is a property that helps to determine whether the sound is high or low. Doppler effect helps to understand this concept easily. The pitch of the sound is mainly calculated based on the frequency of the sound wave arose from the sound source.

As the wellspring of sound waves moves toward an audience, the sound waves draw nearer together, expanding their recurrence and the pitch of the sound.

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Dante drew a diagram of an electric generator.

dimaraw [331]

Answer: There should be one brush on each slip ring.

Explanation:

A device that converts mechanical energy into electrical energy is known as an electric generator. The magnets are kept surrounding armature and axle. The armature rotates in between the magnets. This generates electric current which is detected by the ammeter.

It is based on Faraday's law - when a conductor moves in a magnetic field, an emf is induced in the conductor. Thus, a battery is not required. There should be one brush on each slip ring because the brushes must make contact with the rotating rings to supply current to the coil.

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Which of the following discoveries can be directly attributed to the use of imaging radar

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<span>Imaging radar has given archaeologists "x-ray vision" and helped them locate sites such as the Lost City of Ubar, which was hidden in the sands of the Sahara Desert, and Angkor, and ancient Cambodian kingdom hidden for centuries under the dense tropical forests which covered it.</span>

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3 years ago

At a beach the light is generallypartially polarized owing to reflections off sand and water. At a particular beach on a particu

Ne4ueva [31]

Answer:

a) 0.159

b) 0.84

Explanation:

The Horizontal component is 2.3 times the vertical component

Let the horizontal electric field component = $E_{h}$

Let the vertical electric field component = $E_{v}$

The formula for light intensity is given by:

$I = \frac{E_{m} ^{2} }{2c \mu}$ ..............................(1)

$E_{m}$ is the resolution of the vertical and horizontal components, $E_{h} and E_{v}$

$E_{m} ^{2} = E_{h} ^{2} + E_{v} ^{2}$ ..................(2)

Light intensity before the glasses were put on:

$I_{1} = \frac{E_{m} ^{2} }{2c \mu_{1} }$ .............................(3)

Put equation (2) into equation (3)

$I_{1} = \frac{E_{h} ^{2} + E_{v} ^{2}}{2c \mu_{1} }$ .............................(4)

After the glasses were put on the horizontal component vanishes, i.e. $E_{h} = 0$

$I_{2} = \frac{ E_{v} ^{2}}{2c \mu_{2} }$ ...................................(5)

Divide equation (5) by equation (4)

$\frac{I_{2} }{I_{1} } = \frac{E_{v} ^{2} }{E_{h} ^{2} + E_{v} ^{2}}$ ...............................(6)

But $E_{h} = 2.3E_{v}$ ......................(7)

Insert equation (7) into (6)

$\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{(2.3E_{v})^{2} + E_{v} ^{2} } \\\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{5.29E_{v}^{2} + E_{v} ^{2} }\\\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{6.29E_{v}^{2} }\\\frac{I_{2} }{I_{1} } =\frac{1}{6.29} \\$

$\frac{I_{2} }{I_{1} }= 0.159$

b) When the sunbather lies on his side, the vertical component vanishes, i.e $E_{v} = 0$

$\frac{I_{2} }{I_{1} } = \frac{E_{h} ^{2} }{E_{h} ^{2} + E_{v} ^{2}}$

$\frac{I_{2} }{I_{1} } = \frac{(2.3E_{v} )^{2} }{E_{v} ^{2} +(2.3E_{v} )^{2}}$

$\frac{I_{2} }{I_{1} } = \frac{5.29E_{v}^{2} }{E_{v} ^{2} +5.29E_{v}^{2} }$

$\frac{I_{2} }{I_{1} } = \frac{5.29E_{v}^{2} }{6.29E_{v}^{2} }\\\frac{I_{2} }{I_{1} } = \frac{5.29}{6.29} \\\frac{I_{2} }{I_{1} } = 0.84$

8 0

3 years ago