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aniked [119]
2 years ago
6

Which of the following is a major reason for increased female participation in collegiate athletics?1. Title IX legislation2. mo

re college teams available3. high school teams more available now than in the past4. more female coaches
Physics
1 answer:
choli [55]2 years ago
8 0

Answer:

1. Title IX legislation

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Copper has a specific heat of 0.09 cal/g x C . How much change in temperature would the addition of 8373 cal of heat have on a 5
neonofarm [45]
<h3>Answer:</h3>

172.92 °C

<h3>Explanation:</h3>

Concept being tested: Quantity of heat

We are given;

  • Specific heat capacity of copper as 0.09 cal/g°C
  • Quantity of heat is 8373 calories
  • Mass of copper sample as 538.0 g

We are required to calculate the change in temperature.

  • In this case we need to know that the amount of heat absorbed or gained by a substance is given by the product of mass, specific heat capacity and change in temperature.
  • That is, Q = m × c × ΔT

Therefore, to calculate the change in temperature, ΔT we rearrange the formula;

ΔT = Q ÷ mc

Thus;

ΔT = 8373 cal ÷ (538 g × 0.09 cal/g°C)

    = 172.92 °C

Therefore, the change in temperature will be 172.92 °C

3 0
3 years ago
What was perphaps the greatest challenge of human space flight?
natka813 [3]
Space is more hostile to the human body.

4 0
3 years ago
Read 2 more answers
A 20 liter cylinder of helium at a pressure of 150 atm and a temperature of 27ÁC is used to fill a balloon at 1.00 atm and 37ÁC.
djyliett [7]

<u>Answer</u>

D) 3100 Liters


<u>Explanation</u>

To get the volume if the balloon you need to use the combined equation of the low of gases.

P₁V₁/T₁ = P₂V₂/T₂

(20×150)/(27+273) = (1×V₂)/(37+273)

3000/300 = V₂/310

10 = V₂/310

V₂ = 10 × 310

    = 3100 Liters


7 0
2 years ago
Read 2 more answers
Allison wants to determine the density of a bouncing ball. which metric measurements must she use?
lubasha [3.4K]
Density depends on mass and volume so option D is correct answer. Hope this helps!
3 0
3 years ago
How much heat is needed to warm 0.072kg of gold from 20 celsius and 90 celsius if the specific heat of gold 136 joules
dybincka [34]

Heat supplied to the gold will raise the temperature of the gold from 20 degree Celsius to 90 degree Celsius.

Mass of the gold (m) = 0.072 kg

Temperature change (ΔT) = 90 - 20 = 70 degree Celsius

Specific heat capacity of the gold (c) = 136 J/kg C

Heat supplied = m × c × ΔT

Heat supplied = 0.072 × 136 × 70

Heat supplied = 685.44 Joules

Hence, the heat supplied to the gold to raise the temperature from 20 degree Celsius to 90 degree Celsius = 685.44 Joules

5 0
2 years ago
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