Ask question

Ask question

All categories

2 years ago

10

How far something moves in a specific amount of time

2 answers:

marusya05 [52]2 years ago

6 0

Answer:

SPEED

Explanation:

Svetlanka [38]2 years ago

5 0

Distance is how far something moves in a specific amount of time.

You might be interested in

What is happening at the points on the graph where the slope is flat?

zysi [14]

Answer:

where is graph...............

8 0

2 years ago

The passage helps the reader to draw conclusions about which character's perspective? ºAlec ºAlice ºAlec's father ºAlec's mother

TiliK225 [7]

Answer:

I think it might be A: Alec but tell me if I'm wrong

Explanation:

4 0

2 years ago

Read 2 more answers

A worker with spikes on his shoes pulls on rope that is attached to a box that is resting on a flat, frictionless frozen lake. T

earnstyle [38]

Answer:

a

The free body diagram is shown on the first uploaded image

b

The tension on the rope is $T=39.16 \ N$

Explanation:

From the question we are told that

The mass of the box is m

The tension on the box is T

The angle at which it is pulled is $\theta = 40^o$

The force produced by the strong head wind is $Fw = 30 \ N$

At equilibrium the net force acting on the block along the horizontal axis is zero i.e

$Tcos \theta -F_w = 0$

substituting values

$Tcos (40) -30 = 0$

$Tcos (40) = 30$

$T(0.76604)) = 30$

$T=39.16 \ N$

5 0

2 years ago

The Earth is approximately 150 million kilometers away from the Sun. If light travels at a speed of approximately 300,000 kilome

evablogger [386]

The correct answer to the question is 8.33 minutes.

CALCULATION:

The distance of earth from sun s = 150 million km.

We know one million = 10 lakh = $10^6$

Also 1 km = $10^3\ m$

Hence, the distance s = $150\times 10^6\times 10^3\ m$

= $15\times 10^{10}\ m$

The speed of light c = 300,000 km per second

= $3\times 10^8\ m/s$

We are asked to calculate the time.

The time of the reaching earth is calculated as -

$time=\ \frac{distance}{velocity}$

$t=\ \frac{s}{c}$

$=\ \frac{15\times 10^{10}} {3\times 10^8}\ second$

$=\ 500\ seconds$

We know one minute = 60 second.

Hence, 500 seconds = $\frac{500}{60}\ minute$

= $8.33\ minute$ [ans]

4 0

2 years ago

Read 2 more answers

A 0.1 kg object initially moving with a velocity of 0.2 m/s makes an elastic head-on collision with a 0.15 kg object initially a

Zigmanuir [339]

Answer:

4 %

Explanation:

mass of the object 1, m₁ = 0.1 Kg

initial velocity of object 1,v₁= 0.2 m/s

mass of object 2, m₂ = 0.15 kg

initial speed of the object 2. v₂ = 0 m/s

Kinetic energy retained by the object 1 = ?

using the formula to calculate velocity of the ball after collision

$v_{1f}=\dfrac{m_1-m_2}{m_1+m_2}\ v_1 +\dfrac{2m_2}{m_1+m_2}v_2$

$v_{1f}=\dfrac{m_1-m_2}{m_1+m_2}\ v_1$

$v_{1f}=\dfrac{0.1-0.15}{0.1+0.15}\times 0.2$

$v_{1f}= - 0.04 m/s$

negative sign represent the velocity is in opposite direction after collision.

Initial KE

$KE_1 = \dfrac{1}{2}mv_1^2$

$KE_1 = \dfrac{1}{2}\times 0.1 \times 0.2^2$

$KE_1 = 0.002\ J$

final KE

$KE_2 = \dfrac{1}{2}mv_2^2$

$KE_2= \dfrac{1}{2}\times 0.1 \times 0.04^2$

$KE_2= 0.00008\ J$

% of KE retained

= $\dfrac{KE_2}{KE_1}\times 100$

= $\dfrac{0.00008}{0.002}\times 100$

= 4 %

the percentage of Kinetic energy retained after collision is equal to 4 %

6 0

3 years ago