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navik [9.2K]
3 years ago
13

A rectangular prism has a length of 10 mm, a Width of 15mm and a height of 8mm. How do you find the surface area using the formu

la 2(wh+lw++lh
Mathematics
1 answer:
zhenek [66]3 years ago
8 0

Answer: Use a pice of paper using the explanation

Step-by-step explanation: WH would be width times hight + LW length times width + LH length times hight

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Which equation demonstrates the distributive property?
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B because distributive property goes like this:
a(b+c)
a(b)+a(c)
That's just an example though
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Solve for x:<br> (X+1)(x-3) = 0
Anton [14]

Answer:


Step-by-step explanation:

x= -1 or x=3

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PLZ HELP EVERYTHING IS IN THE PIC.
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Equation: (70 + 70*.05) + (580 + 580*.07) + (620 + 620*.10) = Total Spent

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7 0
3 years ago
Sam wants to build a wooden deck on his patio, which is in the shape of a parallelogram. The area of the patio is 280 ft 2. Find
Radda [10]

Answer: The base is 18.3ft

Sam wants to build a wooden deck on his patio, which is in the shape of a parallelogram. The area of the patio is 280 ft2. Find the base. Round your answer to the nearest foot. (height=5x)(base=6x)

Step-by-step explanation:

Given;

Area = 280ft^2

height = 5x

Base = 6x

The area of the parallelogram A can be written as;

Area = base × height

A = b×h

Substituting the values of Area, base and height.

280 = 5x × 6x

280 = 30x^2

x^2 = 280/30

x = √(280/30)

Since the base = 6x ;

Substituting the value of x.

Base = 6x = 6(√(280/30))

Base = 18.3ft

The base is 18.3ft

4 0
3 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
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